What do you guys know about thermal energy please explain it in the easiest way possible I'm not very smart :(

A 460 g model rocket is on a cart that is rolling to the right at a speed of 3.0 m/s. The rocket engine, when it is fired, exert

ollegr [7]

Answer:

The rocket should be launched at a horizontal distance of <u>6.45 m</u> left of the loop.

Explanation:

Given:

Mass of the rocket model (m) = 460 g = 0.460 kg [1 g = 0.001 kg]

Speed of the cart (v) = 3.0 m/s

Thrust force by the rocket engine (F) = 8.5 N

Vertical height of the loop (y) = 20 m

Let the horizontal distance left to the loop for launch be 'x'. Also, let 't' be the time taken by the rocket to reach the loop.

Now, there are two types of motion associated with the rocket- one is horizontal and the other vertical.

So, we will apply kinematics of motion in the two directions separately.

Vertical motion:

Given:

Force acting in the vertical direction is given as:

$F_y=F-mg=8.5-0.46\times 9.8=3.992\ N$

So, acceleration in the vertical direction is given as:

Acceleration = Force ÷ mass

$a_y=\frac{F_y}{m}=\frac{3.992\ N}{0.46\ kg}=8.678\ m/s^2$

Vertical displacement of rocket is same as the height of loop. So, $y=20\ m$

There is no initial velocity in the vertical direction. So, $u_y=0\ m/s$

Now, applying equation of motion in vertical direction. we have:

$y=u_yt+\frac{1}{2}a_yt^2\\\\20=0+\frac{1}{2}\times 8.678t^2\\\\20=4.339t^2\\\\t^2=\frac{20}{4.339}\\\\t=\sqrt{\frac{20}{4.339}}=2.15\ s$

Now, time taken to reach the loop is 2.15 s.

Horizontal motion:

There is no acceleration in the horizontal motion. So, displacement in the horizontal direction is equal to the product of horizontal speed and time.

Also, displacement of the rocket in the horizontal direction is nothing but the horizontal distance of its launch left of the loop. So,

$x=vt\\\\x=3.0\ m/s\times 2.15\ s\\\\x=6.45\ m$

Therefore, the rocket should be launched at a horizontal distance of 6.45 m left of the loop.

5 0

4 years ago

And metamorphic rock is classified according to its

ICE Princess25 [194]

The answer is basis of texture

8 0

4 years ago

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To create "dry ice," manufacturers compress and cool carbon dioxide gas until it solidifies. Describe what happens to the carbon

tester [92]

Answer:

Explanation:

Temperature is defined as the average kinetic energy of the molecules of a substance. When a substance is cooled, the average kinetic energy of its molecules is reduced tremendously. Thus, the molecules of the substance no longer move at high speeds.

Gases, according to the ideal theory of gas molecules do not associate but are infinitely free and move at very high speeds. However, when cooled, the kinetic energy of these molecules become sufficiently low so as to allow intermolecular association. Secondly, compressing the carbon dioxide gas increases the pressure and decreases its volume. This further makes the carbon dioxide molecules to associate more rapidly. Since dry ice is sublime, CO2 doesn't pass through a liquid state, rather a highly ordered solid-state called dry ice is formed.

3 0

3 years ago

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Consider a perfectly insulated cup (no

tamaranim1 [39]

Answer:

When the heat is heated it will be melted of ice, why it still remain at a constant temperature of 0◦ C.

Explanation:

Solution

The heat given by the heater will be used in melting of the ice, therefore the temperature will remain the same at the degree of 0◦ C.

After the ice is fully melted, the temperature of water will begin to increase with time.

Note: kindly find an attached document of the solutions with diagrams as part of this explanation

7 0

3 years ago

Corbin, an avid skier leaves the horizontal end of a ramp with a velocity of 33.0 m/s and lands 63.0 m from the base the ramp. H

ahrayia [7]

Answer:

Height of ramp = 17.49 m

Explanation:

We have equation of motion , $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

Considering horizontal motion of skier

Initial velocity = 33 m/s, Displacement = 63 m, acceleration = 0 and we need to find time taken to reach ground by the skier.

$63= 33t+\frac{1}{2} *0*t^2\\ \\ t=1.909seconds$

The vertical distance traveled in 1.909 seconds is the height of ramp

Initial velocity = 0 m/s, acceleration = acceleration due to gravity = 9.8 $m/s^2$ , time = 1.909 s and we need to find displacement.

$s= 0*1.909+\frac{1}{2} *9.8*1.909^2\\ \\ s=17.49 m$

So height of ramp = 17.49 m

5 0

3 years ago