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Ann [662]
3 years ago
14

What do you guys know about thermal energy please explain it in the easiest way possible I'm not very smart :(

Physics
1 answer:
cluponka [151]3 years ago
7 0
Thermal energy is heat energy. Thermal means heat, and I bet you're really smart!
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In which direction does a convergent boundary move?
VladimirAG [237]

Answer:

Toward each other teehee merry christmas

Explanation:

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3 years ago
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To make ice, a freezer that is a reverse Carnot engine extracts 37 kJ as heat at -17°C during each cycle, with coefficient of pe
Dvinal [7]

Answer:

a) 6.4 kJ

b) 43.4 kJ

Explanation:

a)

Q_{a} = Heat absorbed = 37 kJ

β  = Coefficient of performance = 5.8

W = Work done

Heat absorbed is given as

Q_{a} = β W

37 = (5.8) W

W = 6.4 kJ

b)

Q  = work per cycle required

Q  = Q_{a} + W

Q  = 37 + 6.4

Q  = 43.4 kJ

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3 years ago
All known matter is made up of Question 1 options:
Tatiana [17]

the answer is (a) molecules

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3 years ago
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Describe the two main ways that energy travels through the Sun.
ValentinkaMS [17]

Answer:

The energy are traveled through the sun in two ways that are:

  • By the radiation
  • By the convection

As, the energy are first traveled outward from the core of the sun and then it get entered in the zone of the radiation and this zone is known as radiative zone in the surface of the sun.In the radiation process some amount of the hydrogen particle are combined and then releases the energy. And the convection is the process of conversion of one form of energy to another form.

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3 years ago
A hot-air balloon is 11.0 m above the ground and rising at a speed of 7.00 m/s. A ball is thrown horizontally from the balloon b
Nesterboy [21]

Answer:

18.6 m/s

Explanation:

h = Initial height of the balloon = 11 m

v_{o} = initial speed of the ball

v_{oy} = initial vertical speed of the ball = 7 m/s

v_{ox} = initial horizontal speed of the ball = 9 m/s

initial speed of the ball is given as

v_{o} = \sqrt{v_{ox}^{2} + v_{oy}^{2}} = \sqrt{9^{2} + 7^{2}} = 11.4 m/s

v_{f} = final speed of the ball as it strikes the ground

m = mass of the ball

Using conservation of energy

Final kinetic energy before striking the ground = Initial potential energy + Initial kinetic energy

(0.5) m v_{f}^{2} = (0.5) m v_{o}^{2} + mgh \\(0.5) v_{f}^{2} = (0.5) v_{o}^{2} + gh\\(0.5) v_{f}^{2} = (0.5) (11.4)^{2} + (9.8)(11)\\(0.5) v_{f}^{2} = 172.78\\v_{f} = 18.6 m/s

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