Question

A disk of radius R = 9.54 cm, is centered at the origin and lies along the y–z plane. The disk has a surface charge density σ = 4.07 × 10-6 C/m2. Evaluate the electric field produced by this disk along the x axis at point P = (1.01 m, 0.00 m). The Coulomb force constant k = 1/(4π ε0) = 8.99 × 109 N·m2/C2.

Answer 1

Answer:

Electric field by charged disk is given as

E = (Charge Density/2u0)*[1 - (z/sqrt(z^2 - R^2))]

R = 9.54cm = 0.0954m, z = 1.01m, Charge density = 4.07 x 10^-6C/m2, e0 = 8.85 x 10^-12F/m.

Substituting all the values in to equation,

E = (2.299 x 10^5) x (8.931 x 10^-3)

E = 2.053 x 10^3N/C

Explanation: