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3 years ago

Sodium, an alkali metal, and chlorine, a halogen, are both in Period 3 of the periodic table. Which element has

Chemistry

1 answer:

melamori03 [73]3 years ago

4 0

Answer:

Chlorine has higher ionization energy.

Explanation:

Sodium is present on left side of periodic table in period 3 while chlorine is present on right side of periodic table in period 3.

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required. Thus chlorine have higher ionization energy as compared to the sodium.

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Consider the reaction of peroxydisulfate ion (S2O2−8) with iodide ion (I−) in aqueous solution: S2O2−8(aq)+3I−(aq)→2SO2−4(aq)+I−

kolbaska11 [484]

Answer:

r = 3.61x $10^{-6}$ M/s

Explanation:

The rate of disappearance (r) is given by the multiplication of the concentrations of the reagents, each one raised of the coefficient of the reaction.

r = k. $[S2O2^{-8} ]^{x} x [I^{-} ]^{y}$

K is the constant of the reaction, and doesn't depends on the concentrations. First, let's find the coefficients x and y. Let's use the first and the second experiments, and lets divide 1º by 2º :

$\frac{r1}{r2} = \frac{0.018^{x} x0.036^{y} }{0.027^xx0.036^y}$

$\frac{2.6x10^{-6}}{3.9x10^{-6}} = (\frac{0.018}{0.027})^xx(\frac{0.036}{0.036})^y$

$0.67 = 0.67^x$

x = 1

Now, to find the coefficient y let's do the same for the experiments 1 and 3:

$\frac{r1}{r3} = \frac{0.018x0.036^y}{0.036x0.054^y}$

$\frac{2.6x10^{-6}}{7.8x10^{-6}} = (\frac{0.018}{0.036})x(\frac{0.036}{0.054})^y$

$0.33 = 0.5x 0.67^y$

$0.67 = 0.67^y$

y = 1

Now, we need to calculate the constant k in whatever experiment. Using the first :

$2.6x10^{-6} = kx0.018x0.036$ $kx6.48x10^{-4} = 2.6x10^{-6}$

k = 4.01x10^{-3} M^{-1}s^{-1}[/tex]

Using the data given,

r = $4.01x10^{-3}x1.8x10^{-2}x5.0x10^{-2}$

r = 3.61x $10^{-6}$ M/s

7 0

3 years ago

How many grams of tris (mw 121.1) would you need to prepare 100 ml of a 100 mm tris solution? _________ grams?

Tems11 [23]

Molarity = (Mass/ molar mass) x (1/ volume of solution in Litres)

Mass = Molarity x molar mass x volume of solution in Litres

Molarity of Tris = 100 mM = 0.1 M

volume of Tris sol. = 100 mL = 0.1 L

molar mass of Tris = 121.1 g/mol

Hence,

mass of Tris = Molarity of Tris x molar mass ofTris x volume of Tris solution

= 0.1 M x 121.1 g/mol x 0.1 L

= 1.211 g

mass of Tris = 1.211 g

7 0

3 years ago

Draw the structure of the fat or oil that would result when a glycerol molecule is

charle [14.2K]

Glycerol will react with 3 butanoic acid molecule to produce glyceryl tributyrate.

Explanation:

You may find the chemical reaction and the structure of molecules in the attached picture.

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3 0

3 years ago

A genetic mutation is always observable in an organism physical appearance True or false

ale4655 [162]

Answer:

false

Explanation:

false, only a small percentage of mutations cause genetic disorders—most have no impact on health or development. For example, some mutations alter a gene's DNA sequence but do not change the function of the protein made by the gene.

4 0

3 years ago

Clear selection

marin [14]

The molarity of the acid given the data from the question is 0.30 M

<h3>Balanced equation </h3>

2HNO₃ + Ba(OH)₂ —> Ba(NO₃)₂ + 2H₂O

From the balanced equation above,

The mole ratio of the acid, HNO₃ (nA) = 2
The mole ratio of the base, Ba(NO₃)₂ (nB) = 1

<h3>How to determine the molarity of the acid</h3>

From the question given above, the following data were obtained:

Volume of acid, HNO₃ (Va) = 39.7 mL
Volume of base, Ba(NO₃)₂ (Vb) = 24 mL
Molarity of base, Ba(NO₃)₂ (Cb) = 0.250 M
Molarity of acid, HNO₃ (Ma) =?

MaVa / MbVb = nA / nB

(Ma × 39.7) / (0.25 × 24) = 2

(Ma × 39.7) / 6 = 2

Cross multiply

Ma × 39.7 = 6 × 2

Ma × 39.7 = 12

Divide both side by 39.7

Ma = 12 / 39.7

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8 0

2 years ago