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Damm [24]
2 years ago
14

How many moles of PCl5 can be produced from 53.0 g of Cl2 (and excess P4)?

Chemistry
1 answer:
elena55 [62]2 years ago
5 0

Answer:

0.299 moles of PCl5

Explanation:

First form an equation based of given information: P4 + Cl2= 4PCl5

Next balance it: P4 + 10Cl2 = 4PCl5

Take your given value (53.0g of Cl2) and divide it by its molar mass to get moles of Cl2: 53.0g/70.906g = 0.747 moles Cl2

Then, multiply by the molar ratio (10Cl2 to 4PCl5): (0.747 x 4 mol PCl5)/10 mol Cl2 = 0.299 moles PCl5

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Answer:

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3 years ago
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Give the oxidation state of the metal species in each complex. ru(cn)(co)4 -
kogti [31]
The given complex ion is as follow,

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Where;
            [ ]  =  Coordination Sphere

            Ru  =  Central Metal Atom  =  <span>Ruthenium

            CN  =  Cyanide Ligand

            CO  =  Carbonyl Ligand

The charge on Ru is calculated as follow,

                               Ru + (CN) + (CO)</span>₄  =  -1
Where;
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            -1  =  Charge on CN

So, Putting values,


                               Ru + (-1) + (0)₄  =  -1

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                               Ru  =  -1 + 1

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Result:
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