Answer:
C - Cl = Polar (Chlorine has an electronegativity of 3.16 and Carbon has 2.55. The difference between the two determines if the bond is polar or non polar, and the difference is 0.61 which means its polar)
Br - Br = Non-polar (Diatomic molecules are non-polar)
N - O= Non-polar ( The electronegativity difference is 0.4, making it non-polar)
P - Cl= Polar (The difference in electronegativity between them is 0.97, making it polar)
Salts dissociate when dissolved in water:
PbSO4 -> Pb2+ + SO4 2-
So there are 2 different particles. 1 mol
of PbSO4 produces 1 mol of Pb2+, and 1 mol of SO4 2- (one of each).
Kps = [Pb2+] [SO4 2-]
We will call “s” the molarity of PbSO4
So the molarity of Pb2+ is also “s” (same
number)
And the molarity of SO4 2- is also “s”
(same number)
Kps = s*s = s2
1.82
× 10-8 = s2
So,
in order to find s, we have to make the square root of 1.82 × 10-8, which is: 0,00013491 M
Answer:
Approximately 
.
Explanation:
Lookup Avogadro's Number: 
(three significant figures.)
Lookup the relative atomic mass of 
, 
, and 
on a modern periodic table:
(For example, the relative atomic mass of is 
means that the mass of one mole of 
atoms would be approximately 
grams on average.)
The question counted the number of 
molecules without using any unit. Avogadro's Number 
helps convert the unit of that count to moles.
Each mole of molecules includes exactly 
of these 
molecules.
molecules would correspond to 
of such molecules.
(Keep more significant figures than required during intermediary steps.)
The formula mass of gives the mass of each mole of 
molecules. The value of the formula mass could be calculated using the relative atomic mass of each element:
.
Calculate the mass of approximately 
of :
.
(Rounded to three significant figures.)
Answer:
Keq = 0.053
7.3 kJ/mol
Explanation:
Let's consider the following isomerization reaction.
glucose 6‑phosphate ⇄ glucose 1 - phosphate
The concentrations at equilibrium are:
[G6P] = 0.19 M
[G1P] = 0.01 M
The concentration equilibrium constant (Keq) is:
Keq = [G1P] / [G6P]
Keq = 0.01 / 0.19
Keq = 0.053
We can find the standard free energy change, ΔG°, of the reaction mixture using the following expression.
ΔG° = -R × T × lnKeq
ΔG° = -8.314 J/mol.K × 298 K × ln0.053
ΔG° = 7.3 × 10³ J/mol = 7.3 kJ/mol
<span>N = +3, H = +1 ,Cl = -1
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