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4 years ago

15

A 205-kg crate is pushed horizontally with a force of 720 n. if the coefficient of friction is 0.20, calculate the acceleration

of the crate. m/s2

1 answer:

Marat540 [252]4 years ago

6 0

Google it...............

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The first charge is pulling on the second. Is the second pulling on the first? Explain your reasoning

Alex73 [517]

Answer:

law of action and reaction.

Explanation:

In Newton's three laws it is established that forces act in pairs, if one body interacts with another the second interacts with the first, this is the so-called law of action and reaction.

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3 years ago

suppose a charge q=+50 uC experiences a force of 0.040 N which points to the right. What is the magnitude and direction of the e

saw5 [17]

Answer:

800 N/C to the right

Explanation:

The relationship between electric force, electric field and charge is

$E=\frac{F}{q}$

where

E is the electric field

F is the force acting on the charge

q is the charge

In this problem, we have

$F = 0.040 N$ is the force

$q=+50 \mu C=+50 \cdot 10^{-6}C$ is the charge

Substituting into the formula, we find the electric field magnitude

$E=\frac{0.040 N}{+50 \cdot 10^{-6}C}=800 N/C$

Concerning the direction:

- The electric field and the force have same directions if the charge is positive

- The electric field and the force have opposite directions if the charge is negative

Here the charge is positive, so the electric field has same direction as the force: therefore, to the right.

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3 years ago