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Ber [7]
3 years ago
6

Rank the work done on the charged particles from highest to lowest

Physics
1 answer:
Artist 52 [7]3 years ago
4 0

Answer:

correct order of work done is given as

2 > 3 > 4 > 1

Explanation:

When positive charge is dragged opposite to electric field then in that case work done is positive while if negative charge is dragged opposite to electric field then the work done is negative

So here we will have

positive work for charge 2, 3 and 4 while for negative charge particle 1 the work done is negative

now here we also know that work done is product of force and displacement

so here work depends on displacement of charge particle

maximum displacement is force particle 2

minimum is for particle 4

so correct order of work done is given as

2 > 3 > 4 > 1

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Maslowich

Text book: We can measure the mass of the text book easily by weighing machine, to measure the volume we need to measure the length, width, and height of the text book by the ruler, by multiplying these dimension we can get the volume of the text book, and by dividing the mass of the book with its volume we can get the density of the book.

Milk Container: We can measure the mass of the milk container easily by weighing machine, now (assuming the milk container is cylindrical in shape) we need to measure its height, and and diameter and by the formula (π*r^2*h) we can measure its volume, and and by dividing the mass  with its volume we can get the density of the milk container.

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3 0
3 years ago
Read 2 more answers
A man does 4,780 J of work in the process of pushing his 2.70 103 kg truck from rest to a speed of v, over a distance of 25.5 m.
wolverine [178]

Answer:

(A) Velocity will be 1.88 m/sec

(b) Force will be 187.45 N

Explanation:

We have given work done = 4780 j

Distance d = 25.5 m

(A) Mass of the truck m = m=2.70\times 10^3kg

We know that kinetic energy is given  by

KE=\frac{1}{2}mv^2

So v=\sqrt{\frac{2KE}{m}}=\sqrt{\frac{2\times 4780}{2.7\times 10^3}}=1.88m/sec

(B) We know that work done is given by

W = Fd

So F=\frac{W}{d}=\frac{4780}{25.5}=187.45N

4 0
3 years ago
Planet Nine is speculated to be on average 20 times farther away from the Sun than Neptune (on average distance from the Sun). H
saveliy_v [14]

Answer:

The distance is 55.636 billion miles, or 528.2 AU.

Explanation:

Since the distance from the Sun to Neptune is 2.7818 billion miles, the distance from the Sun to Planet Nine would be 20 times that, which is:

d=(20)(2781800000\ miles)=55636000000\ miles

or 55.636 billion miles.

Since 1 astronomical unit (AU) is 93 million miles, that distance is also:

d=(55636000000\ miles)(\frac{1AU}{93000000\ miles})=598.2\ AU

6 0
3 years ago
In one type of solar energy system, sunlight heats the air within solar panels, which heats copper tubes filled with water. What
Anna71 [15]
The type of energy that is produced by the system that is described is heat energy. The correct answer is D. 
3 0
3 years ago
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A 2 kg ball is dropped above the surface of Planet X. If the gravitational field strength at the surface of Planet X is 5 N/kg,
Trava [24]

Given data:

* The mass of the ball is 2 kg.

* The gravitational field strength at the surface of planet X is 5 N/kg.

Solution:

The weight of the ball on the planet X is,

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Substituting the known values,

\begin{gathered} W=2\times5 \\ W=10\text{ N} \end{gathered}

Thus, the weight of the ball on the surface of planet X is 10 N.

3 0
1 year ago
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