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3 years ago

Which side of continents have a colder climate than might be expected?

2 answers:

8 0

I'm guessing it depends on the hemisphere, so in the Northern Hemisphere, the North side of continents are colder. In the Southern Hemisphere, southern sides of a continent are colder

Brrunno [24]3 years ago

7 0

Answer:

I'm guessing it depends on the hemisphere, so in the Northern Hemisphere, the North side of continents are colder. In the Southern Hemisphere, southern sides of a continent are colder

Explanation:

i just copied his answer it is a good answer. give him the brainliest answer

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Calculate the angular velocity of the earth in its orbit around the sun.

Orlov [11]

Answer:

$0.0172rad/day=1.99x10^{-7}rad/second$

Explanation:

The definition of angular velocity is as follows:

$\omega=2\pi f$

where $\omega$ is the angular velocity, and $f$ is the frequency.

Frequency can also be represented as:

$f=\frac{1}{T}$

where $T$ is the period, (the time it takes to conclude a cycle)

with this, the angular velocity is:

$\omega=\frac{2\pi}{T}$

The period T of rotation around the sun 365 days, thus, the angular velocity:

$\omega=\frac{2\pi}{365days}=0.0172rad/day$

if we want the angular velocity in rad/second, we need to convert the 365 days to seconds:

Firt conveting to hous

$365days(\frac{24hours}{1day} )=8760hours$

then to minutes

$8760hours(\frac{60minutes}{1hour} )=525,600minutes$

and finally to seconds

$525,600minutes(\frac{60seconds}{1minute})=31,536x10^3seconds$

thus, angular velocity in rad/second is:

$\omega=\frac{2\pi}{31,536x10^3seconds}=1.99x10^{-7}rad/second$

3 0

3 years ago

Two protons (each with q = 1.60 x 10-19)

otez555 [7]

Answer:

230.4 N

Explanation:

From the question given above, the following data were obtained:

Charge (q) of each protons = 1.6×10¯¹⁹ C

Distance apart (r) = 1×10¯¹⁵ m

Force (F) =?

NOTE: Electric constant (K) = 9×10⁹ Nm²/C²

The force exerted can be obtained as follow:

F = Kq₁q₂ / r²

F = 9×10⁹ × (1.6×10¯¹⁹)² / (1×10¯¹⁵)²

F = 9×10⁹ × 2.56×10¯³⁸ / 1×10¯³⁰

F = 2.304×10¯²⁸ / 1×10¯³⁰

F = 230.4 N

Therefore, the force exerted is 230.4 N

5 0

2 years ago

You are beautiful have a nice day <3

Tresset [83]

Answer:

I am?

Explanation:

7 0

3 years ago

Read 2 more answers

when charge 2 is 3.0 m away from charge 1, the strength of the electric force on charge 2 by charge 1 is 0.80 n. if instead, cha

Nikolay [14]

The strength of the electrostatic force is inversely proportional to the square of the distance

between the charges. If the distance is doubled, the force is 1/4.

The new force is 0.80/4 = 0.20 N.

<h3>What is electrostatic force? </h3>

Electrostatic force is the attractive or repulsive force that exists between two charged particles. Also known as Coulomb interaction or Coulomb force. For example, the electrostatic forces between the protons and electrons of an atom are responsible for the stability of the atom.

The force acting along a line joining two point charges is directly proportional to the product of the two charges and inversely proportional to the square of the distance between them.

$F=K |\frac{q_{1} q_{2}}{r^{2} } |$

In the above formula, k is arbitrary and can be chosen to be any positive value. Since k is a constant, I chose to give the value of k as follows:

Therefore, with q₁ and q₂ values of 1 and r = 1 (two charges with 1 Coulomb charge each at a distance of 1 m), we get F = $9 \times 10^9$ N. In the above equation, ε₀ is given as the permittivity of free space and its value in SI units is $8.854\times10^{-12} C^{2} N^{-1} m^{-2}$ .

To learn more about electrostatic force , visit:

brainly.com/question/14870624

#SPJ4

5 0

1 year ago

What is the only "power" unit of measurement in light energy?

n200080 [17]

I believe it wattage or watts

8 0

3 years ago