Y= 0 would be perpendicular because it's a horizontal line, and x= 12 is a vertical line
X=0 would be parallel because they are both vertical lines
Answer:
70.8°
Step-by-step explanation:
The sides and angles are related in a right triangle such that ...
Tan = Opposite/Adjacent
tan(S) = UT/US = 6.6/2.3
The inverse tangent function is used to find the angle from its value:
∠S = arctan(6.6/23)
∠S ≈ 70.8°
It takes 0.57 seconds per copy and he made 6 copies.
6 + 0.57 = 6.57
He added 6 and 0.57 instead of multiplying.
Your original equation has no y-variable. It results in x = -2/3 when you solve for x which is a vertical line. Thus, if you want a line parallel to this that goes through point (- 1, - 4), you just set x equal to the x-value in that ordered pair.
Your parallel line is x = - 1.
I'm going to separate this into sections so it makes more sense for you to read. For the problems with π where you have to round, ask your teacher where to round, unless your textbook specifies it:
A – 100 cm^2
To calculate area of squares, you multiply l • w. It's a square, so all sides are equal, and since we know that one side = 10 cm, the area is 10 • 10 = 100
B – πr^2 (not sure if the r shows up very well, so I'm retyping it in words - pi • radius squared)
C – 25π cm^2 or an approximate round like 78.54 cm^2 (ask your teacher about this – it could be to the nearest tenth, hundredth, etc.)
To find the area of a circle, you must follow the formula πr^2. In this case, the diameter is 10. The radius is half the diameter, so to substitute the values you must find 10 ÷ 2 = 5. So the radius is 5 cm. From there you can substitute r for 5, ending up with π • 5^2. 5^2 = 25, so the area is 25π, or about 78.54, depending on where the question wants you to round.
D – An approximate round (to the nearest hundredth it is 21.46 cm^2)
To find the area of the shaded region, just subtract the circle's area from the square's area, or 100 – 25π ≈ 21.46. Again, though, ask your teacher about where to round, unless your textbook specifies it.
E – dπ (diameter • pi)
F – 10π cm^2 or an approximate round like 31.42 cm^2
The diameter is 10. 10π ≈ 31.42
Hope this helps!
