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Natalija [7]
3 years ago
5

What are produced when HCI reacts with Ca(OH)2?

Chemistry
1 answer:
den301095 [7]3 years ago
3 0
Answer is CaCI2 and H20
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What is the pressure of a fixed volume of hydrogen gas at 38.8°C if it has a pressure of 1.36 atm at 15.0°C?
Rainbow [258]
Hello There! ^_^

Your question: What is the pressure of a fixed volume of hydrogen gas at 38.8°C if it has a pressure of 1.36 atm at 15.0°C..?

Your answer: P1/ T1= P2/ T2
                    
                     Change C to Kelvin
   
                     273+ C= K
               
                     38.3+ 273= 311K
                      
                      15.0+ 273= 288K
                       
                       2.38/ 288= P2/ 311.3
                          
                        740.894= 288 (P2)
                        
                         P2= 2.57 atm.


 Thus, you got you answer!

  Hope this helps!





  

       



    

 

  






4 0
3 years ago
Find the mass of a single one of the molecules or ionic compounds listed below. You must show your work in the correct format an
Lemur [1.5K]
I don’t really know tho
3 0
3 years ago
The Environmental Protection Agency has determined that safe drinking
dmitriy555 [2]

Answer:

b) \bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}

The confidence interval for this case is given (6.21, 6.59)

So we can conclude at 95% of confidence that the true mean for the PH concentration is between 6.21 and 6.59 moles per liter

c) Since the confidence interval not contains the value 7 we reject the hypothesis that the true mean is equal to 7. And the same result was obtained with the t test for the true mean.

Explanation:

We assume that part a is test the claim. And we can conduct the following hypothesis test:

Null hypothesis: \mu =7

Alternative hypothesis \mu \neq 7

The statistic is to check this hypothesi is given by:

t = \frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}

We know the following info from the problem:

\bar X = 6.4 , s=0.5, n =30

Replacing we got:

t = \frac{6.4-7}{\frac{0.5}{\sqrt{30}}}= -6.573

And the p value would be:

p_v= 2*P(Z

Since the p value is very low compared to the significance assumed of 0.05 we have enough evidence to reject the null hypothesis that the true mean is equal to 7 moles/liter

Part b

The confidence interval is given by:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}

The confidence interval for this case is given (6.21, 6.59)

So we can conclude at 95% of confidence that the true mean for the PH concentration is between 6.21 and 6.59 moles per liter

Part c

Since the confidence interval not contains the value 7 we reject the hypothesis that the true mean is equal to 7. And the same result was obtained with the t test for the true mean.

6 0
3 years ago
Liquid 1 has a density of 2.0 g/ml, Liquid 2
Natali5045456 [20]

Liquid 2 because the lower the density the more it floats and the higher the density the more it sinks. The order from top to bottom is liquid 2, liquid 3, liquid 1

8 0
3 years ago
Procaine hydrochloride ( MW = 272.77 g/mol) is used as a local anesthetic. Calculate the molarity of a 4.666 m solution which ha
fenix001 [56]

Answer:

\boxed{\text{2.274 mol/L}}

Explanation:

b = \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}

Assume 1 kg water.

1. Moles of P.HCl

Then we have 4.666 mol of P.HCl

2. Mass of P.HCl

n = 4.666 mol × 272.77 g/mol = 1271.1 g

3. Total mass of solution

m = 1000 g + 1271.1 g = 2271.1 g solution

4. Volume of solution

V = \text{2271.1 g} \times \dfrac{\text{1 mL}}{\text{1.1066 g}} = \text{2052.3 mL} = \text{2.0523 L}

5. Molar concentration  

\begin{array}{rcl}c & = & \dfrac{\text{moles of solute}}{\text{litres of solution}}\\\\c & = & \dfrac{\text{4.666 mol}}{\text{2.0523 L}}\\\\ & = & \text{2.274 mol/L}\\\end{array}\\

\text{The molar concentration of the solution is} \boxed{\textbf{2.274 mol/L}}

5 0
4 years ago
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