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daser333 [38]
4 years ago
10

Assuming that there is a constant partial pressure for oxygen, according to Le Châtelier’s Principle which of the following occu

rs when body temperature decreases during hypothermia?

Chemistry
1 answer:
ololo11 [35]4 years ago
8 0

Answer:

B. The amount of oxygen will decreases

Explanation:

According to Le Châtelier’s Principle, when the condition of the system changes the equilibrium will shift to compensate for the changes. When temperature decrease, the pressure will also decrease and this will shift the equilibrium to the side with exothermic reaction or less molecule count.

The question is not giving the equilibrium reaction of oxygen, so I assume its

O2 + Hb = HbO2

Since the number of molecules in the right side is lower, then the number of oxygen will decrease since the reaction will shift to the right.

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Exactly 1 mol Hg2(NO3)2 contains how many moles of Hg , N , and O ?
marin [14]

In exactly 1 mol Hg₂(NO₃)₂ , there are 2 mol Hg, 2 mol N and 6 mol O.

Since the molecular formula of Hg₂(NO₃)₂ shows that for every mole of the substance, we have 2 moles of Hg, 2 moles of N and 6 moles of O.

So, in exactly 1 mol Hg₂(NO₃)₂ , there are 2 mol Hg, 2 mol N and 6 mol O.

Learn more about number of moles here:

brainly.com/question/3935424

6 0
3 years ago
Fe-54 = 5.845%
FrozenT [24]

Answer:

\boxed {\boxed {\sf 55.76756  \ amu}}

Explanation:

The average atomic mass is the sum of the product of the given masses and their abundances. We have to complete two steps for each isotope, then add all the products together.

<u>Fe-54</u>

Convert the percent abundance to a decimal by dividing by 100.

  • 5.845/100= 0.05845

Multiply the abundance as a decimal by the mass number. This is the number after the element in the isotope symbol (54 amu).

  • 0.005845 * 54=3.1563 amu

<u>Fe-56</u>

Convert the percent to a decimal.

  • 91.754/100=0.91754

Multiply the decimal by the mass number (56 amu).

  • 0.91754 * 56= 51.38224 amu

<u>Fe-58</u>

Convert the percent to a decimal.

  • 2.119/100=0.02119

Multiply by the mass number (58 amu).

  • 0.02119 * 58 = 1.22902 amu

<u>Average Atomic Mass</u>

Add all the products together to find the average atomic mass.

  • 3.1563 amu + 51.38224 amu + 1.22902 amu =55.76756 amu

The average atomic mass given the percent abundance is <u>55.7656 atomic mass units.</u>

8 0
3 years ago
A sample of wood with a mass of 30 g has its
anzhelika [568]

Answer:

0.086J/g°C

Explanation:

The following data were obtained from the question:

Mass (M) = 30g

Initial temperature (T1) = 10°C

Final temperature (T2) = 45°C

Change in temperature (ΔT) = T2 – T1 = 45°C – 10°C = 35°C

Heat (Q) released = 90J

Specific heat capacity (C) of wood =..?

We can obtain the specific heat capacity of the wood as follow:

Q = MCΔT

90 = 30 x C x 35

Divide both side by 30 x 35

C = 90/(30 x 35)

C = 0.086J/g°C.

Therefore, the specific heat capacity of the wood is 0.086J/g°C.

5 0
3 years ago
What would happen if the number of protons were greater than the number of electrons in an atom?
Damm [24]
The atom would have an overall 1+ charge.
8 0
3 years ago
Why is energy a conceptual model?
alexgriva [62]

Answer:

Conceptual energy modeling does not produce the same accurate results as energy modeling with building elements

3 0
3 years ago
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