Answer:
C) 0.121 M
Explanation:
HCl + H₂O = H₃O⁺ + OH⁻
.121M .121M
HCl is a strong acid . It will dissociate almost 100 % so the concentration of acid and hydronium ion formed will be equal . It is to be noted that hydronium ion is formed due to association of H⁺ and H₂O . H⁺ is formed due to ionisation of HCl .
So concentrtion of hydronium ion ( H₃O⁺ ) will be .121 M.
Water and carbon dioxide are waste products released as a direct result of materials
Answer:
47.8 g
Explanation:
Remember the equation for percent yield:
% yield = actual / theoretical
We're given two of the values in the question, so plug n' play:
0.945 = 45.2 / theoretical
theoretical = 47.8 g
Keep in mind you can use mass here without converting to moles because we're working with products only. If you were given a mass of reactants, you would need to convert to moles and using a balanced chemical equation find the corresponding moles of product produced.
Answer:
47%
Explanation:
MgCO₃ (s) → MgO (s) + CO₂ (g)
CaCO₃ (s) → CaO (s) + CO₂ (g)
_______________________
MgCO₃ (s) + CaCO₃ (s) → MgO (s) + CaO (s) + 2CO₂ (g)
MgO: 40.3044 g/mol
MgCO₃: 84.3139 g/mol
CaO:56.0774 g/mol
CaCO₃: 100.0869 g/mol
CO₂: 44.01 g/mol
15.42 g is the total mass of dolomite.
7.85 g is the sum of MgO and CaO produced.
This means that 7.57 g of CO₂ were produced.
44.01 g CO₂_____ 1 mol
7.57 g CO₂ _____ x
x = 0.172 mol CO₂
Considering the global reaction, we had 0.172/2 = 0.086 mol of MgCO₃ in the original sample.
1 mol MgCO₃ _______ 84.3139 g
0.086 mol MgCO₃ ___ y
y = 7.25 g
15.42 g dolomite ______ 100%
7.25 g MgCO₃ ________ z
z = 47%
Answer:
0.92 g
Explanation:
Given data:
Percentage of NaCl = 1.6%
Amount of NaCl present in 57.2 g = ?
Solution:
1.6% of 57.2 g NaCl:
1.6/100× 57.2 g
0.92 g
So in 57.2 g 1.6% of NaCl is 0.92 g.
