One
The molar mass of aluminum from the periodic table is 27
moles = given mass / molar mass
moles = 10 / 27
moles = 0.3704
Two
75 mL * [1 L / 1000 mL] = 0.075 mL
Concentration = 2M = 2 moles / L
Concentration = moles / Volume
2 = moles / 0.075 L Multiply both sides by 0.075
2*0.075 = moles
0.150 moles
Three
Balance Equation: 2Al(s)+ 3CuSO₄ --> Al_2(SO₄)₃ + 3Cu Note the formula for Al_2 (SO_4)_3
2 Al / 0.3704 moles = 3Cu / x Substitute
2 / 0.3704 = 3/x Cross Multiply
2x = 0.3704 * 3
2x = 1.111 Divide by 2
x = 1.111/2
x = 0.555555 moles. of Copper
Four
moles = given mass / molar mass
molar mass Cu = 63.5
moles = 0.555
given mass = moles * molar mass
given mass = 35.28
