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Romashka [77]
3 years ago
11

What is the “cosmic haystack problem”? List as many of its components as you can think of.

Physics
1 answer:
shepuryov [24]3 years ago
8 0

Answer:

About the universe, The problem isn't just that the sky has billions of stars to search but there are also billions of frequencies.

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Are bases chemically the same as acids true or false
Inessa [10]

Answer:

True

Explanation:

True\

I'm not sure but i think it is true la

6 0
3 years ago
How do i know which equation to use for dimensional analysis?
nikitadnepr [17]
You look at the units you want, then try to figure out which units ti multiply by to get the units you have to match the units you want. For example, if you want kg/m^3 and have m/s

You can see that you have a length/time(lets denote it d/t for distance over time) and want mass/volume (lets denote it m/d^3). d/t multiplied by time=d but we want m/d^3 so lets multiply our original d/t by time(t) and mass(m) so d/t(t) (m) =dm. However, we want m/d^3 so we will also have to divide by d^4.

(d/t)(t)(m) /(d^4)=m/d^3 = mass/length^3 =mass/volume which was what we wanted our end result to be.


7 0
4 years ago
What particles make up a plasma of hydrogen?<br><br> A) H+ only<br> B) H+ and e-<br> C) e- only
Alex73 [517]
B)H+ and e-  i hope this helps you<span />
7 0
3 years ago
A 20 gram bullet, traveling horizontally with a velocity of magnitude 350 m/s, is fired into a wooden block with a mass of 0.75,
sertanlavr [38]

Answer:

The kinetic energy is 10.65 joules.

Explanation:

This case can be considered as a collision if we neglect the frictional forces the ball experiences traveling through the wooden block because are lower than the impact forces, then we can use conservation of linear momentum to model this situation considering the system block-bullet.

Linear momentum states total initial momentum (pi) is equal to the final momentum (pf), this is:

p_f=p_i

Total momentum is the sum of individual momentums, in our case the momentum of the ball (pb) plus the momentum of the wooden block (pw), then:

p_{bf}+p_{wf}=p_{bi}+p_{wi}

Linear momentum of an object is defined as mass times velocity, then:

m_bv_{bf}+m_wv_{wf}=m_bv_{bi}+m_wv_{wi}

With vb the velocities of the bullet, mb the mass of the bullet, vw the velocities of the wooden block and mw the mass of the wooden block. Note that the wooden block is initially at rest, that means the initial velocity of the wooden block is zero, then:

m_bv_{bf}+m_wv_{wf}=m_bv_{bi}

Solving the equation for the final velocity of the block:

v_{wf}=\frac{m_bv_{bi} - m_bv_{bf}}{m_w}=\frac{m_b(v_{bi} - v_{bf})}{m_w}

v_{wf}=\frac{0.02(350- 150)}{0.75} =5.33 \frac{m}{s}

(Important: i. The sign of the velocities is important, so we chose positive direction as the direction the bullet moves initially, positive velocities means they are in this same direction.

ii. I assume 0.75 kg for the mass of the wooden block because you didn't provide its unities)

Now with the velocity of the bullet after the collision we can find the kinetic energy using the equation for kinetic energy:

K=\frac{m_wv_{wf}^2}{2}=\frac{(0.75)(5.33)^2}{2}

K=10.65 J

4 0
3 years ago
Read 2 more answers
A ball is dropped from rest from the top of a 6.15-m-tall building, falls straight downward, collides in-elastically with the gr
Mashutka [201]
I'm not sure

That is a hard question

Let me think...
5 0
4 years ago
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