All categories

3 years ago

In which situation is static electricity most likely to form?

Physics

2 answers:

Papessa [141]3 years ago

7 0

Answer:

I'd go for 'Marie drives a car'

Explanation:

Static electricity will possible form in all the scenarios, but is more likely to form when you're driving a car. This is due to the friction between the body of the car and the particles in the air around the body of the car. This is why chains are sometimes attached to fuel tankers when transporting them. The chain is made to touch the ground so that any charge built up can be safely conducted to the earth, reducing the chances of a fire outbreak due to charges igniting the fuel.

Gnoma [55]3 years ago

7 0

Answer:

i think its a, sorry if im wrong

Explanation:

You might be interested in

Jeff’s father is installing a do-it-yourself security system at his house. He needs to get a device from his workshop that conve

Lilit [14]

Answer: buzzer.

The working principle of a buzzer is the conversion of electrical energy to sound energy.

The switch just cuts or permits the flow of current, the motor convertes electrical or other kind of energy into mechanical energy, a bulb converts electrical energy into light and a battery converts chemical energy into electrical energy.

4 0

4 years ago

Read 2 more answers

Kenneth ran a marathon (26.2 miles) in 5.5 hours. What was Kenneth's average speed? (Round your answer to the nearest tenth.) 0.

Anna11 [10]

Answer:

4.8 mph

Explanation:

From the question,

Average speed = total distance/total time

V = d/t....................... Equation 1

Where d = distance, t = time

Given: d = 26.2 miles, t = 5.5 hours.

Substitute these values into equation 1

V = 26.2/5.5

V = 4.76 mph

V ≈ 4.8 mph

5 0

3 years ago

Read 2 more answers

An organism lives in the darkest aquatic ecosystem, where light cannot reach. Which ecosystem is this organism most likely in?

bazaltina [42]

The deep sea vents at the very bottom of the ocean. The thermal vent communities as otherwise stated.

5 0

3 years ago

Read 2 more answers

What is the time period of vibration?

Y_Kistochka [10]

Answer:

A time period is denoted by 'T' . It is the time to complete one cycle of vibration. As the frequency of a wave increases, the time period of the wave decreases. The unit for time period is 'seconds

HOPE IT HELPS :)

PLEASE MARK IT THE BRAINLIEST!

4 0

3 years ago

A particle of mass m moves under a conservative force with potential energy V ( x )= cx/(x2+a2),where c and a are positive const

Anvisha [2.4K]

Answer:

The position of stable equilibrium is -a

And the period of small oscillations must be: c/(ma^3)

Explanation:

Since the potential is:

$V(x) = \frac{c x}{a^2+x^2}$

We first look for a position of stable equilibrium. This posiiton must satisfy two considtions, that the first derivative of the potential must vanish at this point and the second derivative must be positive.

$V'(x) = \frac{c}{a^2+x^2}-\frac{2 c x^2}{\left(a^2+x^2\right)^2}$

Which vanish for

x = a ; x =-a

The second derivative of V(x) is:

$V''(x) = \frac{8 c x^3}{\left(a^2+x^2\right)^3}-\frac{6 c x}{\left(a^2+x^2\right)^2}$

And:

$V''(a) = -\frac{c}{2 a^3}\\V''(-a) = \frac{c}{2 a^3}\\$

Therefore:

The position of stable equilibrium is -a

And the period of small oscillations must be:

$\omega = \sqrt{2 V''(-a)/m} = \sqrt{\frac{c}{a^3 m}}$

(c/(ma^3))^1/2

Let's find the maximum amplitude if the particle starts at this point with velocity v

If this is the case, the total energy will be:

(mv^2)/2

And the maximum amplitude will be

x = a^3/c mv^2 = (m v^2 a^3)/ c

7 0

3 years ago