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2 years ago

Which of these are part of the electromagnetic spectrum?

Physics

2 answers:

bazaltina [42]2 years ago

6 0

Answer: A, C, E

Explanation:

Gamma rays, Microwaves, and Radio waves

Rom4ik [11]2 years ago

3 0

Everything except visible light.

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Why are collisions between galaxies more likely than collisions between stars within a galaxy?

KatRina [158]

Answer:

stars share a gravitational force with the galaxy while nearby galaxies do not share a gravitational field.

Explanation:

stars will not collide because they are bound by a gravitational orbit around the galaxy

8 0

3 years ago

Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton

pishuonlain [190]

Hello!

Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton force is applied to it.

Data:

Hooke represented mathematically his theory with the equation:

F = K * Δx

On what:

F (elastic force) = 2 N

K (elastic constant) = 4 N/cm

Δx (deformation or elongation of the elastic medium or distance from a spring) = ?

Solving:

$F = K * \Delta{x}$

$2\:N = 4\:N/cm*\Delta{x}$

$4\:N/cm*\Delta{x} = 2\:N$

$\Delta{x} = \dfrac{2\:\diagup\!\!\!\!\!N}{4\:\diagup\!\!\!\!\!N/cm}$

simplify by 2

$\Delta{x} = \dfrac{2}{4}\frac{\div2}{\div2}$

$\boxed{\boxed{\Delta{x} = \dfrac{1}{2}\:cm}}\Longleftarrow(distance)\end{array}}\qquad\checkmark$

Answer:

B.) 1/2 cm

_______________________

I Hope this helps, greetings ... Dexteright02! =)

7 0

2 years ago

An object with a mass of 10.5kg is traveling at a velocity of 9m/s. What is the kinetic energy of

WARRIOR [948]

KE = 1/2mv^2
1/2(10.5)(9)^2
1/2(10.5)(81) = 425.25 J

7 0

2 years ago

A railroad car of mass 2.50 3 104 kg is moving with a speed of 4.00 m/s. It collides and couples with three other coupled railro

ipn [44]

Answer:2.5 m/s

37.5KJ

Explanation:

Let $u_1, u_2 , v_f$ be the initial velocity of rail road car ,coupled cars & Final velocity of system respectively.

$m=2.50\times 10^{4}$

Conserving momentum

$mu_1+3mu_2=4mv_f$

$4m+6m=4mv_f$

$v_f=2.5 m/s$

Therefore Final velocity of system is 2.5m/s

(b)Mechanical Energy lost =Initial Kinetic Energy -Final Kinetic Energy

$Initial Kinetic Energy=\frac{1}{2}m\left ( 4^2\right )+\frac{1}{2}m\left ( 2^2\right )=14m J$

$Final Kinetic Energy=\frac{1}{2}4m\left ( 2.5^2\right )=12.5m J$

$Mechanical Energy lost=14m-12.5m=3.75\times 10^4=37.5 KJ$

4 0

3 years ago

If the frequency of the incoming light is increased, will the energy of the ejected electrons increase, decrease, or stay the sa

Arlecino [84]

Answer:

increase

Explanation:

According to Einstein's photoelectric equation; the energy of a photon striking a metal surface is related to the kinetic energy of the ejected photoelectron by the formula;

KE= hf - hfo

Where h is the planks constant, f and fo refer to the frequency of incident photon and the threshold frequency respectively.

Hence, we can clearly see from the foregoing that the kinetic energy of the ejected photoelectron is proportional to the frequency of the incident photon.

Hence, if the frequency of the incident photon is increased, the kinetic energy of the ejected photoelectron increases also.

3 0

2 years ago