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3 years ago

Which is the relationship between algae and fungus?

Physics

1 answer:

aleksklad [387]3 years ago

6 0

the correct answer is mutualism

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A small, 150 g cart is moving at 1.60 m/s on a frictionless track when it collides with a larger, 5.00 kg cart at rest. After th

NemiM [27]

Answer:

Mass of larger cart will be 0.0213 m /sec

Explanation:

We have given mass of small cart $m_1=150gram=0.150kg$

Initial velocity of small cart $v_{1i}=1.6m/sec$

Mass of larger block $m_2=5kg$

Initial velocity of larger cart $v_{2i}=0m/sec$

After the collision velocity of smaller cart $v_{1f}=-0.890m/sec$

Now according conservation of momentum

$m_1v_{1i}+m_2v_{2i}=m_1v{1f}+m_2v_{2f}$

$0.150\times 1.6+5\times 0=0.150\times -0.890+5\times v_{2f}$

$5\times v_{2f}=0.1065$

$v_{2f}=0.0213m/sec$

5 0

3 years ago

A golf ball stays on the tee until the golf club hits it. Which of the following principles best describes why this occurs? A) N

wel

Answer:

C) Newton's law of inertia

Explanation:

The law states that a body will continue in its state of rest or uniform motion unless compel by some external forces (acted upon by an unbalanced force) to act otherwise. In this case the golf will remain in it state because the downward force of gravity is equal to the upward force of normal and the horizontal vector sum of the forces acting on the body is zero.

3 0

3 years ago

A tourist averaged 82km/hr for a 6.5h trip in her volkswagen. how far did she go?

Whitepunk [10]

82 ÷ 6.5 = 12.615384615384... repeating
round = 12.6
12.6 · 6.5 = 81.9
round = 82
She went an average of 12.6 km an hour
Hope this helps! ;)

4 0

3 years ago

The length of a displaced pendulum body which passes its lowest point twice every second

Troyanec [42]

Answer:

0.248 m

Explanation:

The period of a simple pendulum is given by

$T=2\pi \sqrt{\frac{L}{g}}$

where

L is the length of the pendulum

g is the acceleration of gravity

The pendulum in the problem passes its lowest point twice every second: this means: this means that it makes one complete oscillation in one second, so its period is 1 second:

T = 1 s

And using

$g=9.8 m/s^2$