Which is the relationship between algae and fungus?

16. The energy absorbed in 10minutes by an electrical heater is 1.5 MJ. The supply voltage is 240 V. calculate: a) The current d

dsp73

Answer:

If by 1.5 MJ you mean 1.5E6 Joules then

W = P t = power X time

W / t = P power

P = 1.5E6 J / 600 sec = 2500 J / s

P = I V

a) I = 2500 J/s / (240 J/c) = 10.4 C / sec = 10.4 amps

b) Q = I t = 10.4 C / sec * 300 sec = 3120 Coulombs

c) E = P * t = 2500 J / sec * 100 hr * 3600 sec / hr = 9.0E8 Joules

5 0

2 years ago

Two cars collide at an intersection. One car has a mass of 1600 kg and is

pickupchik [31]

The combined momentum is 4000 kg m/s south

Explanation:

The total combined momentum of the two cars is given by the vector addition of the momenta of the two cars.

For this problem, we choose north as positive direction and south as negative direction.

The momentum of the first car travelling north is given by:

$p_1 = m_1 v_1$

where

$m_1 = 1600 kg$ is the mass of the car

$v_1 = +8 m/s$ is its velocity

Substituting,

$p_1 = (1600)(8)=+12800 kg m/s$

The momentum of the second car travelling south is given by:

$p_2 = m_2 v_2$

where

$m_2 = 1400 kg$ is the mass of the car

$v_2= -12 m/s$ is its velocity (negative because the car travels south)

Substituting,

$p_2 = (1400)(-12)=-16800 kg m/s$

And therefore, the combined momentum is

$p=p_1 + p_2 = +12800 + (-16800)=-4000 kg m/s$

where the negative sign means the direction of the total momentum is south.

Learn more about momentum:

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#LearnwithBrainly

4 0

2 years ago

A tuning fork vibrating at 508 Hz falls from rest and accelerates at 9.80 m/s^2. How far below the point of release is the tunin

JulijaS [17]

Answer:

Explanation:

given,

tuning fork vibration = 508 Hz

accelerates = 9.80 m/s²

speed of sound = 343 m/s

observed frequency = 490 Hz

$f_s = f(\dfrac{v}{v-(-v_s)})$

$f_s = f(\dfrac{v}{v+v_s})$

$v_s = v[\dfrac{f_s}{f_o}-1]$

$= 343[\dfrac{508}{490}-1]$

$v_s=12.6 m/s$

distance the tunning fork has fallen

$y_1=\dfrac{v^2}{2a_y}$

$=\dfrac{12.6^2}{2\times 9.8}$

=8.1 m

now, time required for the observed will be

$t = \dfrac{8.1}{343} = 0.023 s$

now, for the distance calculation

$y_2 = u\ t + \dfrac{1}{2}at^2$

$= 12.6\times 0.023 +\dfrac{1}{2}\times 9.8 \times 0.023^2$

=0.293 m

total distance

= 8.1 + 0.293 = 8.392 m

3 0

2 years ago

A car accelerates from 10.0 m/s to 30.0 m/s at a rate of 3.00 m/s2. how far does the car travel while accelerating?

Snezhnost [94]

Answer is in attachment.

3 0

2 years ago

A helicopter, initially hovering 40 feet above the ground, begins to gain altitude at a rate of 21 feet per second. Which of the

Montano1993 [528]

Answer: y = 40 + 21t

Explanation:

Apply the equation of distance covered.

d = vt + C

Where d is the distance covered

v = velocity , t = time

C = constant = initial distance covered

For the case above....

d = y

y(t) = vt + C

But y(0) =40 = C

C = 40ft

velocity v = 21 ft/s

Therefore, the equation of the altitude is given by;

y(t) = 21t +40

y = 40 + 21t

6 0

2 years ago