Which of the following horizons is considered a region of subsoil?

1 answer:

7 0

Let's see. It's definitely not the O horizon, because that layer is at the very top. A is already eliminated. Same thing with the A horizon, that is actually the top soil. C is out. It has to be either B or D. A D layer doesn't exist, so B is out. But the B horizon is considered a region of subsoil. The answer is D: B horizon.

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Among the alkali earth metals, the tendency to react with other substances

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4 years ago

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bekas [8.4K]

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Explanation:

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Someone please answer this percent yield question

pav-90 [236]

<h3>Answer:</h3>

388.94 g N₂

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Using Stoichiometry

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN] 4HCl (g) + 6NO (g) → 5N₂ (g) + 6H₂O (g)

[Given] 404.87 g HCl

<u>Step 2: Identify Conversions</u>

[RxN] 4 mol HCl = 5 mol N₂

Molar Mass of H - 1.01 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of HCl - 1.01 + 35.45 = 36.46 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of N₂ - 2(14.01) = 28.02 g/mol

<u>Step 3: Stoichiometry</u>

<u /> $404.87 \ g \ HCl(\frac{1 \ mol \ HCl}{36.46 \ g \ HCl} )(\frac{5 \ mol \ N_2}{4 \ mol \ HCl} )(\frac{28.02 \ g \ N_2}{1 \ mol \ N_2} )$ = 388.935 g N₂