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lisov135 [29]
3 years ago
15

What are ionic compounds ​

Chemistry
1 answer:
musickatia [10]3 years ago
5 0
Ionic compound is a chemical compound composed of ions held together by electrostatic forces termed ionic bonding
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How many atoms are present in 2g of hydrogen gas​
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Answer:

2 because if you look on the periodic table the number of the element tells you how many atoms is in it

Explanation:

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(20 POINTS) HELP... If you add an unknown liquid to a solution that has a pH of 5, and the pH of the new mixture goes down to 3,
olasank [31]

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D

Explanation:

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If the sun rises at 7:36am and sets at 6:00pm, what times would we use for our data in the 24-hour clock format?
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C is the answer I used to work at McDonald’s I know military time
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3 years ago
Determine the Ka for CH3NH3+ at 25*C. The Kb for CH3NH2 is 4.4 x 10-4.
vfiekz [6]

Answer:

Ka= 2.3 x 10^-11

Explanation:

so Ka x Kb = Kw where Kw=10^-14 at 25 degrees Celsius

plugging in Kb and Kw, we have

Ka x 4.4 x 10^-4 = 10^-14

solving for Ka,

Ka= (10^-14)/(4.4 x 10^-4)

Ka= 2.3 x 10^-11

8 0
3 years ago
If helium effuses through a porous barrier in 1.34 min, how much time (in min) would it take the same amount of ammonia to effus
timofeeve [1]

Answer:

The time taken the same amount of ammonia to effuse through the same barrier under the same conditions is 2.76 minutes.

Explanation:

Let the volume of the helium gas be = V

Time taken by the helium gas = t = 1.34 min

Effusion rate of helium gas = R=\frac{V}{1.34 min}

If V volume of ammonia effuse through same porous barrier the effusion rate of ammonia gas will be given as:

R'=\frac{V}{t'}

Using Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

Molar mass of helium gas = M = 4 g/mol

Molar mass of ammonia gas = M' = 17 g/mol

\frac{R}{R'}=\sqrt{\frac{M'}{M}}

\frac{\frac{V}{1.34 min}}{\frac{V}{t'}}=\sqrt{\frac{17 g/mol}{4 g/mol}}

t'=1.34 min\times \sqrt{\frac{17 g/mol}{4 g/mol}}=2.76 min

The time taken the same amount of ammonia to effuse through the same barrier under the same conditions is 2.76 minutes.

8 0
3 years ago
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