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Rzqust [24]
3 years ago
8

a chamber with a fixed volume of 1.0 meters cubed contains a monatomic gas at 3.00 *10^K. The chamber is heated to a temperature

of 400 K. This operation requires 10.0 J of heat. How many gas molecules are in the chamber
Physics
1 answer:
igomit [66]3 years ago
3 0

Answer:

Explanation:

Given

Volume of fixed chamber V=1 m^3

Initial Temperature T_1=300 K

Final Temperature T_2=400 K

Heat Supplied Q=10 J

From First law of thermodynamics

Change in internal energy of the system is equal to heat added minus work done by the system

\Delta U=Q-W

as the volume is fixed therefore work

W=\int PdV=0

thus \Delta U=mc_v\Delta T=Q

c_v for mono-atomic gas is 12.471 J/K-mol

n\times 12.471\times (400-300)=10

n=0.008018 mol

and 1 mole contains 6.022\times 10^{23} molecules

thus  No of molecules=0.008018\times 6.022\times 10^{23}

No of molecules=4.82\times 10^{21} molecules

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Answer:

Explanation:

Given that,

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As you tune your radio to a higher frequency, from 88.5 FM to 103.3 FM, the wavelength of the wave that you are tuning in
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\omega =  Angular frequency of the wave on the string

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v = Speed of the wave

At the same time each of this terms have its own definition, i.e,

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\mu = \frac{m}{l}

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Replacing this terms and the first equation we have that

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