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Sophie [7]
3 years ago
15

How to find average speed in physics

Physics
1 answer:
Triss [41]3 years ago
7 0

Answer: you divide total distance by time. To get the time, divide total distance by speed. To get distance,  multiply speed times the amount of time.

Explanation:

I hope this helps

You might be interested in
A 1,103 kg car traveling at 18 m/s to the south collides with a 4,919 kg truck that is initially at rest at a stoplight. The car
Zigmanuir [339]

ANSWER

3.30\text{ m/s}

EXPLANATION

Parameters given:

Mass of car, mc = 1103 kg

Mass of truck, mt = 4919 kg

Initial velocity of car, uc = 18 m/s

Inital velocity of truck = 0 m/s

To solve this problem, we have to apply the law of conservation of momentum, which states that the total momentum of a system is constant.

This implies that:

m_cu_c+m_tu_t=m_cv_c+m_tv_t

Since the car and the truck stick together after the collision, they will have the same final velocity.

Hence:

m_cu_c+m_tu_t=(m_c+m_t)v_{}_{}

Substitute the given values and solve for v (final velocity):

\begin{gathered} (1103\cdot18)+(4919\cdot0)=(1103+4919)v \\ \Rightarrow19854=6022v \\ \Rightarrow v=\frac{19854}{6022} \\ v=3.30\text{ m/s} \end{gathered}

That is the final velocity of the two-vehicle mass.

8 0
1 year ago
4. A steel cable spanning a river is 220.000 m long when the temperature is 30.°C.
romanna [79]

Answer:

219.9208  m

Explanation:

The new length is given by

New length= Original length *(1-Temperature change*coefficient of

thermal expansion of steel)

Here, the change in temperature is 30^{\circ}-0^{\circ}= 30^{\circ}

New length= 220.000(1-30*12x10^{-6}=219.9208m

Therefore, the new length will be 219.9208 m

5 0
3 years ago
A thin metallic spherical shell of radius 0.357 m has a total charge of 5.03 times 10^-6 C placed on it. At the center of the sh
Artyom0805 [142]

Answer:

The electric field is 5.623\times10^{4}\ N/C

Explanation:

Given that,

Radius = 0.357 m

Charge Q=5.03\times10^{-6}\ C

Point charge q=4.15\times10^{-6}\ C

Distance = 0.815 m

We need to calculate the total electric field

Using formula of electric field

E=\dfrac{1}{4\pi\epsilon_{0}}\dfrac{q}{r^2}

Where, q = point charge

r = distance

Put the value into the formula

E=\dfrac{9\times10^{9}\times4.15\times10^{-6}}{(0.815)^2}

E=5.623\times10^{4}\ N/C

Hence, The electric field is 5.623\times10^{4}\ N/C

4 0
3 years ago
Light is incident on a piece of glass in air at an angle of 33 degrees from the normal. If the index of refraction of the glass
lilavasa [31]
About 21 to 22 degrees 

as below

4 0
3 years ago
Two charges +q and -q are situated at certain distance, at the point exactly midway betwee them what happens on electric field a
Luden [163]

Answer: Electric field is not zero but potential is zero

Explanation:

In science, charge, also recognized as electric charge, electrical charge, or electrostatic charge and expressed q, is a component of a unit of body that reveals the extent to which it has more or fewer electrons than protons.

Considering the direction of the electric field is of positive to negative charge. Therefore, it determination be toward due −q also due to both the charges.

But for potential, it is a scalar quantity, so the sum of potential due to all the charges will be zero.

Henceforth, the option (c) Electric field is not zero but potential is zero is the correct answer.

a incorect

From the above statements, we could conclude that option (c) Electric field is not zero, but potential is zero is the correct answer. So, the option (a) Electric field and potential both are zero is an incorrect solution.

b incorect

Among all the options, the option (c) Electric field is not zero but potential is zero is the correct answer.

Therefore, the option (b) Electric field is zero but potential is not zero is an incorrect solution

d) is incorrect

It has been explained that the option (c) Electric field is not zero but potential is zero is the correct answer.

Hence, the option (d) Electric field is not zero but potential is zero is an incorrect solution.

7 0
3 years ago
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