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3 years ago

How to find average speed in physics

1 answer:

7 0

Answer: you divide total distance by time. To get the time, divide total distance by speed. To get distance, multiply speed times the amount of time.

Explanation:

I hope this helps

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Amanda goes shopping for light bulbs. In the light bulb aisle, she finds the following incandescent light bulbs. Can you help he

Luden [163]

Answer:

The least efficient light bulb is the first one (25 W - 210 Lumen)

Explanation:

Efficiency can be defined as what you want to obtain over what you need to produce it. In this case Eff= Wattage / Lumen. For each light bulb, their efficiency is: 8.4 / 11.12 / 15.7 Lum/W

4 0

3 years ago

A 0.086 kg bullet is fired at 266 m/s and collides with a 6.3 kg wooden block that is initially stationary. The bullet embeds in

olga2289 [7]

Answer:

The value of speed of wooden block at the instant after the collision $V_f =$ 262.41 $\frac{m}{s}$

Explanation:

Given data

Mass of block = 6.3 kg

Mass of bullet = 0.086 kg

Velocity of bullet $V_0$ = 266 $\frac{m}{s}$

Final velocity of whole system is

$V_f = M_{b}\frac{ V_0}{M_b + (M_{block})}$

Put all the values in above formula we get

$V_f = \frac{(6.3)(266)}{(6.3 + 0.086)}$

$V_f =$ 262.41 $\frac{m}{s}$

This is the value of speed of wooden block at the instant after the collision.

7 0

3 years ago

Ingrid is jogging at 9 km/h, she tosses a relay stick at 16 km/h to her teammate. How fast is the relay stick moving relative to

sesenic [268]

Answer:

27km/h

Explanation:

3 0

3 years ago

Two movers are pushing a large crate with a force of 60.0 n each. one pushes north, the other east. what is the equilibrant forc

romanna [79]

To get the solution you must need to draw a force triangle. Attach the head of the 60N north force arrow with the tail of the 60N east force arrow. The subsequent is the arrow connecting he tail and head of the two arrows.
You get a right angled triangle, and the resultant is (60^2 + 60^2) ^0.5 = 84.85 N or 85 N northeast.

8 0

3 years ago

A block with a mass of 0.600 kg is connected to a spring, displaced in the positive direction a distance of 50.0 cm from equilib

tankabanditka [31]

Answer:

Explanation:

The amplitude of the oscillation under SHM will be .5 m and the equation of

SHM can be written as follows

x = .5 sin(ωt + π/2) , here the initial phase is π/2 because when t = 0 , x = A ( amplitude) , ω is angular frequency.

x = .5 cosωt

given , when t = .2 s , x = .35 m

.35 = .5 cos ωt

ωt = .79

ω = .79 / .20

= 3.95 rad /s

period of oscillation

T = 2π / ω

= 2 x 3.14 / 3.95

= 1.6 s

b )

ω = $\sqrt{\frac{k}{m} }$

ω² = k / m

k = ω² x m

= 3.95² x .6

= 9.36 N/s

c )

v = ω $\sqrt{(a^2-x^2)}$

At t = .2 , x = .35

v = 3.95 $\sqrt{.5^2-.35^2}$

= 3.95 x .357

= 1.41 m/ s

d )

Acceleration at x

a = ω² x

= 3.95 x .35

= 1.3825 m s⁻²

7 0

3 years ago