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dalvyx [7]
3 years ago
5

3. During a tug-of-war, Team A pulls with a

Physics
2 answers:
Neko [114]3 years ago
8 0

Answer:

8000 - 5000 =3000

Explanation:

Damm [24]3 years ago
5 0

<u>Answer:</u> The net force on the rope is 3000 N towards Team B.

<u>Explanation:</u>

Balanced force is defined as the forces that gets cancelled out when equal forces are acting in the opposite direction. The net force on the system comes out to be 0.

Unbalanced force is defined as the forces that does not get cancelled out because unequal forces act on the system in opposite direction. The motion of the object is in the direction of net force.

According to the question:

Force applied by Team A on the rope in tug-of-war = 5000 N

Force applied by Team B on the rope in tug-of-war = 8000 N

Net force acting on the rope = 8000 - 5000 = 3000 N (acting towards Team B)

Hence, the net force on the rope is 3000 N towards Team B.

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Explanation:

700N right

to get the net force

you gotta let one direction be the negative ( the smaller force)

so the total force towards the left is 100N ( 60 + 40= 100)

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so without even calculating , you can know that it will be moving towards the right because right force > left force

your add both forces ( remember 100 N is negative)

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hope this helps

this is just one method that helped me understand

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