Answer:
This is simple, if it has a high flammability, and you light it on fire, then that would be a chemical change.
Explanation:
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Volume of Hydrogen V1 = 351mL
Temperature T1 = 20 = 20 + 273 = 293 K
Temperature T2 = 38 = 38 + 273 = 311 K
We have V1 x T2 = V2 x T1
So V2 = (V1 x T2) / T1 = (351 x 311) / 293 = 372.56
Volume at 38 C = 373 ml
Answer:

Explanation:
Hello!
In this case, since we are considering an gas, which can be considered as idea, we can write the ideal gas equation in order to write it in terms of density rather than moles and volume:

Whereas MM is the molar mass of the gas. Now, since we can identify the initial and final states, we can cancel out R and MM since they remain the same:

It means we can compute the final density as shown below:

Now, we plug in to obtain:

Regards!
Replicating experiments
(If u don’t mind can y mark me brainiest it would really help :) )
Well as an spontaneous reaction will have a negative gibbs free energy (delta g) and a positive e cell and also the E cell is also measured in V, then your answer is the first one: ΔG = –295kJ, E°cell = +1.53 v. Hope this works