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White raven [17]
3 years ago
14

A Cyclist rode at an average speed of 10mph for 15 miles. how long was the ride

Chemistry
2 answers:
Setler79 [48]3 years ago
6 0
Hey there Abigaildonaimor,

A cyclist rode at an average speed of 10mph for 15 miles. How long was the ride?

Answer:

Time = Distance / Rate
         = 15 miles / 10mph
         = 1.5 hours

Hope this helps :D

<em>~Natasha♥</em>
Len [333]3 years ago
5 0
Hey,

The answer is A

peace
-Alex
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Explain how a substances flammability can indicate a chemical change.
Marat540 [252]

Answer:

This is simple, if it has a high flammability, and you light it on fire, then that would be a chemical change.

Explanation:

May I have brainliest please? :)

4 0
3 years ago
A sample of hydrogen occupies a volume of 351 mL at a temperature of 20 degrees Celsius. What is the new volume if the temperatu
xeze [42]
Volume of Hydrogen V1 = 351mL 
Temperature T1 = 20 = 20 + 273 = 293 K 
Temperature T2 = 38 = 38 + 273 = 311 K 
We have V1 x T2 = V2 x T1 
So V2 = (V1 x T2) / T1 = (351 x 311) / 293 = 372.56 
Volume at 38 C = 373 ml
6 0
3 years ago
A sample of gas has a density of 0.53 g/L at 225 K and under a pressure of 108.8 kPa. Find the density of the gas at 345 K under
sukhopar [10]

Answer:

\rho _2=0.22g/L

Explanation:

Hello!

In this case, since we are considering an gas, which can be considered as idea, we can write the ideal gas equation in order to write it in terms of density rather than moles and volume:

PV=nRT\\\\PV=\frac{m}{MM} RT\\\\P*MM=\frac{m}{V} RT\\\\P*MM=\rho RT

Whereas MM is the molar mass of the gas. Now, since we can identify the initial and final states, we can cancel out R and MM since they remain the same:

\frac{P_1*MM}{P_2*MM} =\frac{\rho _1RT_1}{\rho _2RT_2} \\\\\frac{P_1}{P_2} =\frac{\rho _1T_1}{\rho _2T_2}

It means we can compute the final density as shown below:

\rho _2=\frac{\rho _1T_1P_2}{P_1T_2}

Now, we plug in to obtain:

\rho _2=\frac{0.53g/L*225K*68.3kPa}{345K*108.8kPa}\\\\\rho _2=0.22g/L

Regards!

8 0
3 years ago
One way that scientists ensure that data are reliable is through
Vesna [10]
Replicating experiments

(If u don’t mind can y mark me brainiest it would really help :) )
4 0
4 years ago
Which two values for `DeltaG` and E°cell correctly indicate a spontaneous reaction?
Mila [183]

Well as an spontaneous reaction will have a negative gibbs free energy (delta g) and a positive e cell and also the E cell is also measured in V, then your answer is the first one: ΔG = –295kJ, E°cell = +1.53 v. Hope this works



4 0
3 years ago
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