Point charges q1 and q2 are separated by a distance of 60 cm along a horizontal axis.

Physics

1 answer:

amm18123 years ago

8 0

Answer:

38 cm from q1(right)

Explanation:

Given, q1 = 3q2 , r = 60cm = 0.6 m

Let that point be situated at a distance of 'x' m from q1.

Electric field must be same from both sides to be in equilibrium(where EF is 0).

=> k q1/x² = k q2/(0.6 - x)²

=> q1(0.6 - x)² = q2(x)²

=> 3q2(0.6 - x)² = q2(x)²

=> 3(0.6 - x)² = x²

=> √3(0.6 - x) = ± x

=> 0.6√3 = x(1 + √3)

=> 1.03/2.73 = x

≈ 0.38 m = 38 cm = x

You might be interested in

Would it be better to collide head-on with an identical car traveling at the same speed or collide with a stationary brick wall?

attashe74 [19]

It makes no difference. The momentum of either car goes to zero in both cases.

6 0

3 years ago

A worker does 25 J of work lifting a bucket, then sets the bucket back down in the same place. What is the total net work done o

Vera_Pavlovna [14]

Answer:

0 J

Explanation:

As work is force times displacement, if no displacement occurs, no work occurs.

5 0

2 years ago

Why is it important for engineers to design bumper cars safely

rosijanka [135]

Answer:

Cars have bumpers designed to protect the body of the car from minor damage during low-speed collisions. ... They will use the engineering design process to design and build bumpers to protect the main parts of their car from damage, and use their knowledge of Newton's third law to explain what they observe.

Explanation:

3 0

3 years ago

Read 2 more answers

Diagram shows the velocity time graph for a particle moving in 16 seconds.

Leya [2.2K]

Answer:

The detailed calculations are shown below;

Explanation:

a)The maximum acceleration of the particle:

It is seen that the maximum change in velocity is at the time between 8s to 10s.

Maximum acceleration: $\frac{V}{t}$