Answer:
Explanation:
Newton’s second law states that the acceleration a of an object is proportional to the force F acting on it is inversely proportional to its mass m. The mathematical expression for the second law of motion is given by :
F = m × a
F is the applied force
m is the mass of the object
a is the acceleration due to gravity
We need to find the dimensions of force. The dimension of force m and a are as follows :
So, the dimension of force F is, . Hence, this is the required solution.
Answer:
4.05 m/s
Explanation:
We shall represent the different velocity in vector form
Newton runs due north at 3.90 m/s, with respect to standing Daniel .
V_n = 3.9 j
Let Pauli runs with respect to standing Daniel with velocity X .
Then relative velocity of Newton with respect to running Pauli will be
3.9 j - X
Give that
relative velocity of Newton with respect to running Pauli = 1.1 i ( 1.1 due east )
So
3.9 j - X = 1.1 i
X = -1.1 i + 3.9 j .
Magnitude of X
X² = 1.1 ² + 3.9²
X = 4.05 m/s
So Pauli runs with respect to standing Daniel with velocity 4.05 m /s .
Direction will be , west of north at angle θ ,
Tan θ = 1.1 / 3.9
Answer:
Spacecraft's speed relative to Earth is 0.14c .
Explanation:
Let v be the speed of the spacecraft with respect to Earth's frame. According to special theory of relativity, there is time dilation i.e. given by the relation :
t = t₀γ
Here t is time measured in moving frame, t₀ is time measured in rest frame and γ is constant.
We know that γ =
Here c is the speed of light.
So, t = .......(1)
According to the problem, the time measure in Earth's frame is :
t₀ = 1 hr = 60 min =60 x 60 s = 3600 s
The time measured in the space craft frame is :
t = 3601 s
Substitute t and t₀ in equation (1) :
3601 =
v = 0.14 c