Answer:
Molar mass of acetic acid = 60 g/mol
Explanation:
Molar mass of any compound is the sum of the atomic masses of all the atoms of elements present in it.
Molar mass of acetic acid:
Formula:
CH₃COOH
Atomic mass of carbon = 12 g/mol
Atomic mass of hydrogen = 1 g/mol
Atomic mass of oxygen = 16 g/mol
Molar mass of acetic acid = 12×2 + 1 × 4 + 16× 2
Molar mass of acetic acid = 60 g/mol
Answer:
Viruses could have a high mutation rate
Explanation:
Viruses replicate very fast when they enter into the bloodstream. This isn’t however the real cause of why a secondary immune system isn’t possible against them.
The main cause is because they mutate rapidly. The immune system already has an idea of the genetic composition of the pathogen exposed to previously and knows how to fight it. But the viruses undergoes some genetic alterations which then makes it hard for the secondary immune response to attack and kill them.
Human hair. Human hair as energy because it is living so, it is most likely to give up electrons.
Answer:
a)The equilibrium constant at 686°C is 0.527.
b) Concentrations of all the gases be when equilibrium is reestablished:
![[CO_2]=0.2834 M](https://tex.z-dn.net/?f=%5BCO_2%5D%3D0.2834%20M)
![[H_2]=0.02440 M](https://tex.z-dn.net/?f=%5BH_2%5D%3D0.02440%20M)
![[CO]=0.06660 M](https://tex.z-dn.net/?f=%5BCO%5D%3D0.06660%20M)
![[H_2O]=0.05460 M](https://tex.z-dn.net/?f=%5BH_2O%5D%3D0.05460%20M)
Explanation:
a) 
Equilibrium concentrations:
![[CO]=0.0500 M](https://tex.z-dn.net/?f=%5BCO%5D%3D0.0500%20M)
![[H_2]=0.0410 M](https://tex.z-dn.net/?f=%5BH_2%5D%3D0.0410%20M)
![[CO_2]=0.0880 M](https://tex.z-dn.net/?f=%5BCO_2%5D%3D0.0880%20M)
![[H_2O]=0.0380 M](https://tex.z-dn.net/?f=%5BH_2O%5D%3D0.0380%20M)
The value of an equilibrium constant will be given as:
![K_c=\frac{[CO][H_2O]}{[CO_2][H_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCO%5D%5BH_2O%5D%7D%7B%5BCO_2%5D%5BH_2%5D%7D)
The equilibrium constant at 686°C is 0.527.
b)
Initially
0.30 M 0.0410 M 0.0500 M 0.0380 M
At reestablishment of an equilibrium;
(0.30-x) M (0.0410-x) M (0.0500+x) M (0.0380+x) M
The value of an equilibrium constant will be given as:
Solving for x;
x = 0.0166
Concentrations of all the gases be when equilibrium is reestablished:
![[CO_2]=(0.30-x)=(0.30-0.0166) M=0.2834 M](https://tex.z-dn.net/?f=%5BCO_2%5D%3D%280.30-x%29%3D%280.30-0.0166%29%20M%3D0.2834%20M)
![[H_2]=(0.0410-x)=(0.0410-0.0166) M=0.02440 M](https://tex.z-dn.net/?f=%5BH_2%5D%3D%280.0410-x%29%3D%280.0410-0.0166%29%20M%3D0.02440%20M)
![[CO]=(0.0500+x)=(0.0500+0.0166) M=0.06660 M](https://tex.z-dn.net/?f=%5BCO%5D%3D%280.0500%2Bx%29%3D%280.0500%2B0.0166%29%20M%3D0.06660%20M)
![[H_2O]=(0.0380+x)=(0.0380+0.0166) M=0.05460 M](https://tex.z-dn.net/?f=%5BH_2O%5D%3D%280.0380%2Bx%29%3D%280.0380%2B0.0166%29%20M%3D0.05460%20M)
