Answer:
N = 3032 turns
Explanation:
The magnetic field produced by a solenoid is described by
B = μ₀ n I
Where is the permittivity in a vacuum with a value of 4π 10⁻⁷ N /A², n is the turn density and I the current
Let's apply this equation to the problem, the turn density is the number of turns per unit length, in this case it is the same magnet length
L = 8 cm = 0.08 m
Let's calculate
B = μ₀ N/L I
N = B L / μ₀ I
N = 0.10 0.08 / (4π 10⁻⁷ 2.1)
N = 3,032 103 turns
Answer:
Explanation:
If the passage of the waves is one crest every 2.5 seconds, then that is the frequency of the wave, f.
The distance between the 2 crests (or troughs) is the wavelength, λ.
We want the velocity of this wave. The equation that relates these 3 things is
and filling in:
so
v = 2.5(2.0) and
v = 5.0 m/s
Is the production of electricity by magnetic field.
There are two types of generator which is <u>D</u><u>.</u><u>C</u><u> </u>generator . And A.C <em>g</em><em>e</em><em>n</em><em>e</em><em>r</em><em>a</em><em>t</em><em>o</em><em>r</em>
A.C gen consist of rectangular coil,brushes and permanent magnet
According to the external force mechanical energy used to rotate coil, due to magnetic flux produced by permanent magnet create induced current, this is to according to flemmings right hand rule of electromagnetic induction the rotating coil will produce current
I hope that will help.
Answer: 363 Ω.
Explanation:
In a series AC circuit excited by a sinusoidal voltage source, the magnitude of the impedance is found to be as follows:
Z = √((R^2 )+〖(XL-XC)〗^2) (1)
In order to find the values for the inductive and capacitive reactances, as they depend on the frequency, we need first to find the voltage source frequency.
We are told that it has been set to 5.6 times the resonance frequency.
At resonance, the inductive and capacitive reactances are equal each other in magnitude, so from this relationship, we can find out the resonance frequency fo as follows:
fo = 1/2π√LC = 286 Hz
So, we find f to be as follows:
f = 1,600 Hz
Replacing in the value of XL and Xc in (1), we can find the magnitude of the impedance Z at this frequency, as follows:
Z = 363 Ω
