Answer:
Kinetic friction is an inhibitory force that is present when a body or object begins to move. It should be noted that this force is in the opposite direction to the movement of the body that slides with respect to a surface and parallel to that surface.
In addition, this friction varies according to the surface characteristics and the material properties of the bodies that slide in this surface. Being quantified by the coefficient of kinetic friction 
, which is dimensionless.
The correct answer is the following.
The forces that act on the piano are: 2) gravitational force acting on the piano (piano's weight). 5) force of the floor on the piano (normal force). 7) force of Chadwick on the piano.
As we see in the picture that I have attached is Chadwick pushing the piano in a horizontal plane. So Chadwick is applying a force that produces an acceleration. It is his force on the piano plus the acceleration of the weight of the piano, it's a gravitational force. This is pure physics applied to an object.
Answer:
4. It is infrared.
Explanation:
the photosystems on the chlorophyll absorb light at 600-700nm
Answer:
The ion has fewer electrons
Explanation:
As Rubidium forms a positive ion Rb⁺ the number of electrons becomes fewer for the atom.
- A positive charge on an ion indicates that the number of protons for the atom is greater than the number of electrons.
- This leaves a net positive charge on the atom.
- For a negatively charged ion, the number of electrons is more than the number of protons because they have gained additional electrons.
- In a neutral atom, the number of protons and electrons are the same.
Answer:
The work done on the air is 4.699 x 10⁶ Joules
Explanation:
Given;
increase in air volume, ΔV = 0.227 m³
net pressure of the air, P = 2.07 x 10⁷ Pa
The work done on the air is given by;
W = PΔV
Where;
W is the work done on the air
P is the net pressure
ΔV is the increase in air volume
Substitute the given values and solve for work done;
W = (2.07 x 10⁷ Pa) (0.227 m³)
W = 4.699 x 10⁶ Joules
Therefore, the work done on the air is 4.699 x 10⁶ Joules
