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faltersainse [42]
3 years ago
5

A parachute works because the canvas of the parachute is acted upon by __________.

Physics
2 answers:
Ne4ueva [31]3 years ago
8 0
The question is asking to choose among the following choices that could complete the question about the inertia, base on my research and further investigation, the possible answer would be letter B. Gravity. I hope you are satisfied with my answer and feel free to ask for more 
Tema [17]3 years ago
5 0

Answer:

Inertia

Explanation:

Hope this helps:)

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A) Find the gravitational field strength of an asteroid with the mass of 3.2 * 10^3 kg and an average radius of 30 km when at a
MrMuchimi

a) 1.96\cdot 10^{-16} m/s^2

The gravitational field strength near the surface of the asteroid is given by:

g=\frac{GM}{(R+h)^2}

where

G is the gravitational constant

M is the mass of the asteroid

R the radius of the asteroid

h is the distance from the surface

Substituting the data of the asteroid:

M=3.2\cdot 10^3 kg is the mass

R=30 km = 30000 m is the radius of the asteroid

h=3 km = 3000 m is the distance from the surface

We find

g=\frac{(6.67\cdot 10^{-11})(3.2\cdot 10^3)}{(30000+3000)^2}=1.96\cdot 10^{-16} m/s^2

b) i)  5.53\cdot 10^9 s

The acceleration of the astronaut popped out at 3 km from the surface is exactly that calculated at part a):

g=1.96\cdot 10^{-16} m/s^2

So, since its motion is at constant acceleration, we can find the time he takes to reach the surface using suvat equations:

s=ut+\frac{1}{2}gt^2

where

s = 3 km = 3000 m is his displacement to reach the surface

u = 0 is his initial velocity

t is the time

Solving for t,

t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(3000)}{1.96\cdot 10^{-16} m/s^2}}=5.53\cdot 10^9 s

b) ii) 1.08\cdot 10^{-6} m/s

Again, we can use another suvat equation:

v=u+gt

where

v is the final velocity

u is the initial velocity

g is the acceleration of gravity

t is the time

Since we have

u = 0

t=5.53\cdot 10^9 s

g=1.96\cdot 10^{-16} m/s^2

The velocity of the astronaut at the surface will be

v=0+(1.96\cdot 10^{-16} m/s^2)(5.53\cdot 10^9)=1.08\cdot 10^{-6} m/s

b) iii) 175 years

The duration of one year here is

T=3.16\cdot 10^7 s

And the time it takes for the astronaut to reach the surface of the asteroid is

t=5.53\cdot 10^9 s

Therefore, to find the number of years, we just need to divide the total time by the duration of one year:

n=\frac{t}{T}=\frac{5.53\cdot 10^9 s}{3.16\cdot 10^7}=175

So, the astronaut will take 175 years to reach the surface.

8 0
3 years ago
A bullet with a mass of 0.04-kg is traveling horizontally at 1400 m/s when it strikes a stationary target that is balanced on th
hammer [34]

The speed of the target with the bullet lodged in it is 5.6 m/s.

<h3>What is speed?</h3>

This is the rate of change of distance.

To calculate the speed of the target and the bullet lodged, we use the formula below.

Formula:

  • V = mu/(m+M)............. Equation 1

Where:

  • V = Speed of the target and the bullet
  • m = mass of the bullet
  • M = mass of the target
  • u = Initial speed of the target

From the question,

Given:

  • m = 0.04 kg
  • u = 1400 m/s
  • M = 9.96 kg

Substitute these values into equation 1

  • V = (0.04×1400)/(0.04+9.96)
  • V = 56/10
  • V = 5.6 m/s

Hence, the speed of the target with the bullet lodged in it is 5.6 m/s.

Learn more about speed here: brainly.com/question/6504879

#SPJ1

4 0
2 years ago
How much time passes when an object travels at a constant speed of 17 m/s over a distance of 323 m? Identify Variables, write fo
k0ka [10]

Answer: 19 s

Explanation:

The relationship between speed, distance  and time is given by:

velocity= distance/time

time= distance/velocity= 323 m/17 m/s= 19 s

8 0
3 years ago
Calculate the change in entropy that occurs in the system when 3.10 mole of isopropyl alcohol (C3H8O) melts at its melting point
ozzi

Answer:

3.10 mole of C3H8O change in entropy is 89.54 J/K

Explanation:

Given data

mole = 3.10 moles

temperature = -89.5∘C = -89 + 273 = 183.5 K

ΔH∘fus = 5.37 kJ/mol =  5.3 ×10^3 J/mol

to find out

change in entropy

solution

we know change in entropy is ΔH∘fus / melting point

put these value so we get change in entropy that is

change in entropy 5.3 ×10^3 / 183.5

change in entropy is 28.88 J/mol-K

so we say 1 mole of C3H8O change in entropy is 28.88 J/mol-K

and for the  3.10 mole of C3H8O change in entropy is 3.10 ×28.88  J/K

3.10 mole of C3H8O change in entropy is 89.54 J/K

4 0
3 years ago
Read 2 more answers
What type of nuclear decay releases energy but not a particle?
statuscvo [17]
I believe gamma decay but i may be wrong
7 0
3 years ago
Read 2 more answers
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