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shepuryov [24]
3 years ago
5

Lightning produces a maximum air temperature on the order of 104K, whereas a nuclear explosion produces a temperature on the ord

er of 107K. Find the order of magnitude of the wavelength radiated with greatest intensity by each of these sources. Name the part of the EM spectrum where you would expect to radiate most strongly.
Physics
1 answer:
gtnhenbr [62]3 years ago
5 0

Answer:

tex]2.898\times 10^{-7}\ \text{m}[/tex] ultraviolet region

2.898\times 10^{-10}\ \text{m} x-ray region

Explanation:

T = Temperature

b = Constant of proportionality = 2.898\times 10^{-3}\ \text{m K}

\lambda = Wavelength

T=10^4\ \text{K}

From Wein's law we have

\lambda=\dfrac{b}{T}\\\Rightarrow \lambda=\dfrac{2.898\times 10^{-3}}{10^4}\\\Rightarrow \lambda=2.898\times 10^{-7}\ \text{m}

The wavelength of the radiation will be 2.898\times 10^{-7}\ \text{m} and it is in the ultraviolet region.

T=10^7\ \text{K}

\lambda=\dfrac{2.898\times 10^{-3}}{10^7}\\\Rightarrow \lambda=2.898\times 10^{-10}\ \text{m}

The wavelength of the radiation will be 2.898\times 10^{-10}\ \text{m} and it is in the x-ray region.

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Define neuron and nerve<br>cell​
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Alisiya [41]
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3 years ago
un resorte de 10cm de longitud recibe una magnitud de fuerza que lo estira hasta medir 15cm ¿cual es la magnitud de la tension u
Ber [7]

Answer: 0.5

Explanation:

The modulus of elasticity (called <em>"alargamiento unitario"</em> in spanish) \epsilon of a spring is given by the following formula:

\epsilon=\frac{\Delta L}{L}

Where:

L=10 cm  is the original length of the spring

\Delta L=L_{f}-L  is the elongation of the spring, being L_{f}=15 cm the length of the spring after a force is applied to it.

\epsilon=\frac{L_{f}-L}{L}=\frac{15 cm - 10 cm}{10 cm}

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8 0
3 years ago
Miles is camping in Glacier National Park. In the midst of a glacier canyon,
valentina_108 [34]

Answer:

t=1.623 sec

Explanation:

The distance traveled before the echo is had is:

distance=2d, d=280\ m\\\\=280\times 2\\\\=560 \ m

Given the speed of sound as v=345m/s, we use the speed equation to solve for t:

v=\frac{d}{t}\\\\345\ m/s=\frac{560m}{t}\\\\t=\frac{560}{360}\\\\=1.623 \ s

Hence, it takes 1.623 seconds to hear the echo.

8 0
3 years ago
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