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shepuryov [24]
3 years ago
5

Lightning produces a maximum air temperature on the order of 104K, whereas a nuclear explosion produces a temperature on the ord

er of 107K. Find the order of magnitude of the wavelength radiated with greatest intensity by each of these sources. Name the part of the EM spectrum where you would expect to radiate most strongly.
Physics
1 answer:
gtnhenbr [62]3 years ago
5 0

Answer:

tex]2.898\times 10^{-7}\ \text{m}[/tex] ultraviolet region

2.898\times 10^{-10}\ \text{m} x-ray region

Explanation:

T = Temperature

b = Constant of proportionality = 2.898\times 10^{-3}\ \text{m K}

\lambda = Wavelength

T=10^4\ \text{K}

From Wein's law we have

\lambda=\dfrac{b}{T}\\\Rightarrow \lambda=\dfrac{2.898\times 10^{-3}}{10^4}\\\Rightarrow \lambda=2.898\times 10^{-7}\ \text{m}

The wavelength of the radiation will be 2.898\times 10^{-7}\ \text{m} and it is in the ultraviolet region.

T=10^7\ \text{K}

\lambda=\dfrac{2.898\times 10^{-3}}{10^7}\\\Rightarrow \lambda=2.898\times 10^{-10}\ \text{m}

The wavelength of the radiation will be 2.898\times 10^{-10}\ \text{m} and it is in the x-ray region.

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1.5 hours

Explanation:

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t=75 miles ÷ 50 miles per hour = 1.5 hours

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No, he won't be drowned.

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Depth of the pool( in feet ) = x ( say ) < 4 feet,

Since, the depth of the pool < height of the student,

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A size-5 soccer ball of diameter 22.6 cm and mass 426 g rolls up a hill without slipping, reaching a maximum height of 5.00 m ab
maria [59]

Answer:

W = 0.678 rad/s  

Explanation:

Using the conservation of energy:

E_i =E_f

Roll up and hill without slipping is the sumatory of two energys, rotational and translational, so:

\frac{1}{2}IW^2+ \frac{1}{2}mV^2 = mgh

where I is the moment of inertia, W the angular velocity at the base of the hill, m the mass of the ball, V the velocity at the base of the hill, g the gravity and h the altitude.

First, we will find the moment of inertia as:

I =\frac{2}{3}mR^2

where m is the mass and R the radius, so:

I =\frac{2}{3}(0.426kg)(11.3m)^2

I = 36.26 Kg*m^2

Then, replacing values on the initial equation, we get:

\frac{1}{2}(36.26)W^2+ \frac{1}{2}(0.426kg)V^2 = (0.426kg)(9.8)(5m)

also we know that:

V =WR

so:

\frac{1}{2}(36.26)W^2+ \frac{1}{2}(0.426kg)W^2R^2 = (0.426kg)(9.8)(5m)

Finally, solving for W, we get:

W^2(\frac{1}{2}(36.26)+ \frac{1}{2}(0.426kg)(11.3m)^2) = (0.426kg)(9.8)(5m)

W = 0.678 rad/s

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Answer:Air Mass

Explanation:

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