Passengers which are facing forward in the direction that train is moving, their bodies will move forward in application of sudden stop of train.
<h3>What is force of inertia?</h3>
Force of inertia is the force which acts in the opposite direction of the force of acceleration acting on the body.
Given infroamtion-
The passengers are facing forward in the direction that the train is moving.
The train comes to a sudden stop.
Lets see what happens step wise-
- Here, the train in moving in the forward direction and the passengers are also facing forward in the direction that the train is moving.
- Now the train comes to a sudden stop. By this sudden stop the train stops suddenly but all the object including the passengers is still travelling forward due to the inertia force.
- Thus all the passenger will tend to move in the direction as they are still travelling.
Hence, passengers which are facing forward in the direction that train is moving, their bodies will move forward in application of sudden stop of train.
Learn more about the force of inertia here;
brainly.com/question/10454047
It is subduction;) good luck on the others my man
Option B & Option D is your correct answers.
'cause here, atom has eight electrons in it's valence shell, so it means it has stable structure which falls in group 18
Hope this helps!
Answer:
B)
The magnitude of induced emf in the conducting loop is 0.99 mV.
Explanation:
Rate of increase in magnetic field per unit time = 0.090 T/s
Area of the conducting loop = 110 cm^2 = 0.0110 m^2
Electromagnetic induction is the production of an emf or voltage in a coil of wire due to a changing magnetic field through the coil.
Induced e.m.f is given as:
EMF = (-N*change in magnetic field/time)*Area
EMF = rate of change of magnetic field per unit time * Area
EMF = 0.090 * 0.0110
EMF = 0.00099 V
EMF = 0.99 mV
The answer to the question is shown below:
We all know that formula for solving work done is the force multiplied by distance covered:
Work done = Force x distance
Distance = 5m
Force = 500 N
Work done = 500 N * 5m
Work done = 2500 J
