1. The structural unit of nucleic acids are composed of repeating units of monomers called nucleotides. Nucelotides are composed of three functional groups: sugars which are specifically pentoses (5-Carbon sugars), phosphate group and nitrogenous base.
2. The two major classes of nucleic acids in the body are the DNA or deoxyribonucleic acids and RNA or ribonucleic acids.
3.
a. Based on the nitrogenous bases and sugar, the DNA has a deoxyribose as the sugar and its 4 bases are adenine, guanine, cytosine and thymine. For RNA, the sugar is ribose while its 4 bases are <span>adenine, guanine, cytosine, and uracil
b. Based on the </span>general three-dimensional structure, DNA is a double stranded β-helix with a long chain of nucleotides. RNA is composed of a shorter chain with a single strand α-helix structure.
c. Based on r<span>elative functions, the DNA is responsible for storing the genetic information while the RNA is responsible for transporting the genetic information to the ribosomes which synthesize proteins.</span>
Like mitosis, meiosis is a form of eukaryotic cell division. However, these two processes distribute genetic material among the resulting daughter cells in very different ways. meiosis gives rise to four unique daughter cells, each of which has half the number of chromosomes as the parent cell. Because meiosis creates cells that are destined to become gametes (or reproductive cells), this reduction in chromosome number is critical — without it, the union of two gametes during fertilization would result in offspring with twice the normal number of chromosomes!
Explanation:
where,
R = Gas constant = 
T = temperature = ![600^oC=[273.15+600]K=873.15 K](https://tex.z-dn.net/?f=600%5EoC%3D%5B273.15%2B600%5DK%3D873.15%20K)
= equilibrium constant at 600°C = 0.900
Putting values in above equation, we get:
The ΔG° of the reaction at 764.85 J/mol is 764.85 J/mol.
Equilibrium constant at 600°C = 
Equilibrium constant at 1000°C = 
![T_1=[273.15+600]K=873.15 K](https://tex.z-dn.net/?f=T_1%3D%5B273.15%2B600%5DK%3D873.15%20K)
![T_2=[273.15+1000]K=1273.15 K](https://tex.z-dn.net/?f=T_2%3D%5B273.15%2B1000%5DK%3D1273.15%20K)
![\ln \frac{K_2}{K_1}=\frac{\Delta H^o}{R}\times [\frac{1}{T_1}-\frac{1}{T_2}]](https://tex.z-dn.net/?f=%5Cln%20%5Cfrac%7BK_2%7D%7BK_1%7D%3D%5Cfrac%7B%5CDelta%20H%5Eo%7D%7BR%7D%5Ctimes%20%5B%5Cfrac%7B1%7D%7BT_1%7D-%5Cfrac%7B1%7D%7BT_2%7D%5D)
![\ln \frac{0.396}{0.900}=\frac{\Delta H^o}{8.314 J/mol K}\times [\frac{1}{873.15 K}-\frac{1}{1273.15 K}]](https://tex.z-dn.net/?f=%5Cln%20%5Cfrac%7B0.396%7D%7B0.900%7D%3D%5Cfrac%7B%5CDelta%20H%5Eo%7D%7B8.314%20J%2Fmol%20K%7D%5Ctimes%20%5B%5Cfrac%7B1%7D%7B873.15%20K%7D-%5Cfrac%7B1%7D%7B1273.15%20K%7D%5D)
The ΔH° of the reaction at 600 C is -18,969.30 J/mol.
ΔG° = ΔH° - TΔS°
764.85 J/mol = -18,969.30 J/mol - 873.15 K × ΔS°
ΔS° = -22.60 J/K mol
The ΔS° of the reaction at 600 C is -22.60 J/K mol.
Partial pressure of carbon dioxide = 
Partial pressure of carbon monoxide = 
Where 
mole fraction of carbon dioxide and carbon monoxide gas.
The expression of is given by:
Mole fraction of carbon dioxide at 600°C is 0.474.
Answer:
Liquid and gas
Explanation:
Liquid and gas are the phases of matter that take the shape of container.
This is very simple to imagine, if we have a piece of rock and we put it in a container, it will not take the shape of container as it already has a definite shape and volume. Liquid when put in a container takes the shape of container but varies in volume as per the container.
However, the gas phases is the phase of matter that perfectly takes the shape of container and occupies all the volume of container as well.
If we recall Dalton's Law of Partial Pressures we can see that the pressure exerted by the gas components in a container is same like the pressure exerted by the gas alone. These partial pressures of the component of gas combine in such a way that they exert total pressure equal to the constituents' pressure on the container. This way gases occupy all the volume of a container and take the shape of a container they're placed in.
Hope it help!
