The magnitude of electric field is produced by the electrons at a certain distance.
E = kQ/r²
where:
E = electric field produced
Q = charge
r = distance
k = Coulomb Law constant 9 x10^9<span> N. m</span>2<span> / C</span><span>2
Given are the following:
Q = </span><span>1.602 × 10^–19 C
</span><span>r = 38 x 10^-9 m
Substitue the given:
E = </span>
E = 998.476 kN/C
At 0.1m, the restoring force would be 25 Newtons. It would probably not be possible to stretch to 5 meters because that would cause a restoring force of 1250 Newtons.
<span>The flywheel is solid cylindrical disc. Moment of inertial = ½ * mass * radius^2
Mass = 40.0 kg
Radius = ½ * 76.0 cm = 38 cm = 0.38 meter
Moment of inertial = ½ * 41 * 0.36^2
Convert rpm to radians/second
The distance of 1 revolution = 1 circumference = 2 * π * r
The number of radians/s in 1 revolution = 2 * π
1 minute = 60 seconds
1 revolution per minute = 2 * π radians / 60 seconds = π/30 rad/s
Initial angular velocity = 500 * π/30 = 16.667 * π rad/s
170 revolutions = 170 * 2 * π = 340 * π radians
The flywheel’s initial angular velocity = 16.667 * π rad/s. It decelerated at the rate of 1.071 rad/s^2 for 48.89 seconds.
θ = ωi * t + ½ * α * t^2
θ = 16.667 * π * 48.89 + ½ * -1.071 * 48.89^2
2559.9 - 1280
θ = 1280 radians</span>
Answer:
d = 4217 m
Explanation:
Case 1.
Initial velocity, u = 0
Acceleration, a = 2.2 m/s²
Let d₁ is the distance in case 1. Using second equation of motion as follows :
![d_1=ut+\dfrac{1}{2}a_1t_1^2\\\\\text{Here, u =0}\\\\d_1=\dfrac{1}{2}\times 2.2\times 10^2\\\\d_1=110\ m](https://tex.z-dn.net/?f=d_1%3Dut%2B%5Cdfrac%7B1%7D%7B2%7Da_1t_1%5E2%5C%5C%5C%5C%5Ctext%7BHere%2C%20u%20%3D0%7D%5C%5C%5C%5Cd_1%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%202.2%5Ctimes%2010%5E2%5C%5C%5C%5Cd_1%3D110%5C%20m)
Let d₂ in the distance in case 2. Using second equation of motion as follows :
![d_2=ut+\dfrac{1}{2}a_2t_2^2\\\\\text{Here, u =0}\\\\d_2=\dfrac{1}{2}\times 1.5\times 74^2\\\\d_2=4107\ m](https://tex.z-dn.net/?f=d_2%3Dut%2B%5Cdfrac%7B1%7D%7B2%7Da_2t_2%5E2%5C%5C%5C%5C%5Ctext%7BHere%2C%20u%20%3D0%7D%5C%5C%5C%5Cd_2%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%201.5%5Ctimes%2074%5E2%5C%5C%5C%5Cd_2%3D4107%5C%20m)
Total distance,
D = d₁ + d₂
D = 110 + 4107
D = 4217 m
Hence, the total distance covered is 4217 m.
Given Information:
slope angle = θ = 30°
spring constant = k = 30 N/m
compressed length = x = 10 cm = 0.10 m
mass of ice cube = m = 63 g = 0.063 kg
Required Information:
distance traveled by ice cube = d = ?
Answer:
distance traveled by ice cube = 0.48 m
Explanation:
Using the the principle of conversation of energy, the following relation holds true for this case,
mgh = 1/2*kx²
h = 1/2*kx²/mg
Where h is the height of the slope, m is the mass of ice cube, k is the spring constant and x is the compressed length o the spring and g is gravitational acceleration.
h = 1/2*kx²/mg
h = 1/2*30(0.1)²/0.063*9.8
h = 0.242 m
From trigonometry ratio,
sinθ = h/d
d = h/sinθ
d = 0.242/sin(30)
d = 0.48 m
Therefore, when the ice cube is released, it will travel a total distance 0.48 up the slope before reversing direction.