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3 years ago

Mass=1.01 kg; volume =1000cm3

Chemistry

1 answer:

guajiro [1.7K]3 years ago

7 0

Density = 1.01 g/cm^3 or 1.01 kg/dm^3 or 1010 kg/m^3

Density = mass/volume = 1010 g/1000 cm^3 = 1.01 g/cm^3 = 1.01 kg/dm^3

= 1010 kg/m^3

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How does weathering break down or change rocks

tatyana61 [14]

Well weathering adds different elements to rocks which they might not be used to. For example, very hard rain & harsh winds could push a rock, causing it to fall & break off into smaller rocks.

3 0

3 years ago

What is the percent composition of phosphoric acid H3PO4

Agata [3.3K]

Hey there!:

Molar mass H3PO4 = 97.9952 g/mol

Atomic Masses :

H = 1.00794 a.m.u

P = 30.973762 a.m.u

O = 15.9994 a.m.u

H % = [ ( 1.00794 * 3 ) / 97.9952 ] * 100

H% = 3.0857 %

P % = [ ( 30.973762 * 1 ) / 97.9952 ] * 100

P% = 31.6074 %

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3 years ago

3.25 x 10+8 nm2 divide by 6.5 x 10+6 nm =

Vesnalui [34]

Answer: 50 nm

Explanation: Two steps:

1. Divide 3.25/6.5 = 0.5

2. Divide 10^8/10^6 = 10^2

nm^2/nm = nm

Combine: 0.5x10^2 nm

or 50 nm

8 0

3 years ago

What is the pH of a mixture of 0.042 M NaH2PO4 and 0.058 M Na2HPO4? Hint: The pKa of phosphate is 6.86.

AlekseyPX

Answer:

The pH value of the mixture will be 7.00

Explanation:

Mono and disodium hydrogen phosphate mixture act as a buffer to maintain pH value around 7. Henderson–Hasselbalch equation is used to determine the pH value of a buffer mixture, which is mathematically expressed as,

$pH=pK_{a} + log(\frac{[Base]}{[Acid]})$

According to the given conditions, the equation will become as follow

$pH=pK_{a} + log(\frac{[Na_{2}HPO_{4} ]}{[NaH_{2}PO_{4}]})$

The base and acid are assigned by observing the pKa values of both the compounds; smaller value means more acidic. NaH₂PO₄ has a pKa value of 6.86, while Na₂HPO₄ has a pKa value of 12.32 (not given, but it's a constant). Another more easy way is to the count the acidic hydrogen in the molecular formula; the compound with more acidic hydrogens will be assigned acidic and vice versa.

Placing all the given data we obtain,

$pH=6.86 + log(\frac{0.058}{0.042})$

$pH=7.00$

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3 years ago

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Answer:

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2 years ago