What is the most common grip used in racket sports?

2. A wave on a rope has a wavelength of 2.0 m and a frequency of 2.0 Hz. What is the speed of the

TEA [102]

Answer:

4 m/s or 4 meters per second.

Explanation:

In order to calculate the speed of wave, you multiply the wavelength in meters and the frequency of the Wave in Hertz. 2 times 2 equals 4. The wave speed is always in m/s considering that the wavelength is also in meters.

7 0

4 years ago

HELP ME FAST PLZZ 48 BRAINLY POINTS TO WHO EVER ANSWER!

Elis [28]

Answer:

25

Explanation:

I looked at it and its 25

4 0

3 years ago

Read 2 more answers

The principal limitation of wind power is unpredictability. Please select the best answer from the choices provided

Lady_Fox [76]

<span>The correct answer is A: True. Although the ability to forecast weather has increased over the years, the ability to predict when and how much wind will occur at any given time and place is difficult. Weather conditions are subject to constant change and while some areas are known to have more wind than others, there is no guarantee about how much wind there will be as weather patterns vary in consistency.</span>

6 0

3 years ago

Read 2 more answers

For a railgun, determine the current required to accelerate a 1000kg space vehicle to earths escape velocity on 10km of track wi

Troyanec [42]

Answer:

the current is 15.68 × $10^{5}$ A

Explanation:

mass = 1000 kg

magnetic fied = 2T

rail separation = 2m

escape velocity is 11.2km/s = 11.2 × $10^{3}$ m/s

distance = 10 km = $10^{4}$ m

to find out

determine the current

solution

we know force F = I×L×B

here I is current and L is rail separation and B is magnetic field

so F = I ×2×2 = 4 I

so

acceleration is a = $\frac{F}{mass}$

a = $\frac{4I}{1000}$ m/s²

so equation of motion

v²-u² = 2 a S

here u is initial velocity and S is distance and a is acceleration and v is final velocity

11.2 × $10^{3}$ - 0 = 2× $\frac{4I}{1000}$ × $10^{4}$

solve we get I

I = 15.68 × $10^{5}$ A

so the current is 15.68 × $10^{5}$ A

4 0

3 years ago

A 1500 kg car moving with a speed of 20 m/s collides with a utility pole and is brought to rest in 0.30 s. Find the magnitude of

storchak [24]

Answer:

-100000 N.

Explanation:

Force: This can be defined as the product of the mass of a body and it's acceleration. The S.I unit of Force is Newton(N). The Formula of force is given as,

F = ma ........................... Equation 1

Where F = Average force exerted on the car, m = mass of the car, acceleration of the car, a = acceleration of the car.

a = (v-u)/t..................... Equation 2

Where v = Final velocity, u = Initial velocity, t = time.

Substitute equation 2 into equation 1

F = m(v-u)/t............. Equation 3

Given: m = 1500 kg, u = 20 m/s, v = 0 m/s (brought to rest), t = 0.3 s.

Substitute into equation 3

F = 1500(0-20)/0.3

F = 1500(-20)/0.3

F = -100000 N.

Note: The negative sign is due to the fact that the force exerted on the car by the pole is equal and opposite the force of the car.

7 0

3 years ago