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Maksim231197 [3]
1 year ago
15

If a 0.08 kg cell phone falls off a table at 15 m/s, then what is its kinetic energy right before it hits the ground?

Physics
1 answer:
Mariana [72]1 year ago
7 0

The kinetic energy of the phone right before it hits the ground is 9J.

<h3>Kinetic energy of the phone</h3>

The kinetic energy of the phone right before it hits the ground is calculated as follows;

K.E = ¹/₂mv²

where;

  • m is mass of the phone
  • v is velocity of the phone

K.E = ¹/₂(0.08)(15)²

K.E = 9 J

Thus, the kinetic energy of the phone right before it hits the ground is 9J.

Learn more about kinetic energy here: brainly.com/question/25959744

#SPJ1

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option C

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When the biker move in the circular track centripetal force is acting on the biker which is being balanced by the normal force.

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Answer:

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Explanation:

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<h3>Why is graphite a solid lubricant?</h3>

We know that graphite is composed of layers. These hexagonal layers are held together by weak Van Der Walls forces and as such are able to slide over each other. The carbon atom in each layer are held together by strong covalent bonds.

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Learn more about graphite:brainly.com/question/11095487

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AVprozaik [17]

Answer:

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