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Greeley [361]
3 years ago
13

Human fat has a density of 0.918 g/cm^3. How much volume (in cm^3) is gained by a person who gains 10.1 lbs of pure fat?

Chemistry
1 answer:
elena55 [62]3 years ago
8 0
Density is a physical property which describes the mass of a substance per unit of volume of the substance. It is expressed as Density = m / V and it has units like g/cm^3. We use the density given to solve the problem.
<span>
10.1 lbs (1 kg/2.2 lb)(1000 g / 1kg) / 0.918 g / cm^3 = 5001 cm^3</span>
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ollegr [7]

Answer:

3.80g

Explanation:

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2 years ago
Which equation represents a conservation of atoms?
weqwewe [10]

Answer:

4) 4Fe + 3O₂ → 2Fe₂O₃

Explanation:

4Fe + 3O₂ → 2Fe₂O₃

In this equation the numbers of atoms are same in both side. There are four iron and six oxygen atoms are present on left and right side of equation. That's why atoms are conserved. This equation completely followed the law of conservation of mass.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

This law was given by french chemist  Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

8 0
2 years ago
H₂ (2)<br> → H.<br> H₂(8)<br> +<br> 2(g)<br> wer
Gre4nikov [31]

The given question is incomplete. The complete question is:

In the chemical reaction: , with 8 grams of and 16 grams of and the reaction goes to completion, what is the excess reactant and how much of that would remain?

A) 6 grams of  

B) 7 grams of  

C) 8 grams of

D) 12 grams of

E) 14 grams of

Answer: A) 6 grams of H_2

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} H_2=\frac{8g}{2g/mol}=4moles

\text{Moles of} O_2=\frac{16g}{32g/mol}=0.5moles

2H_2(g)+O_2(g)\rightarrow 2H_2O(g)  

According to stoichiometry :

1 moles of O_2 require 2 moles of H_2

Thus 0.5 moles of O_2 will require=\frac{2}{1}\times 0.5=1.0moles  of H_2

Thus O_2 is the limiting reagent as it limits the formation of product and H_2 is the excess reagent.

(4.0-1.0) = 3.0 moles of  are left unreacted

Mass of remained=

Thus 6.0 g of H_2 will remain.

4 0
2 years ago
3. How many atoms are in 2 moles of Carbon?
CaHeK987 [17]

Answer:

Explanation:

In one mole of carbon, there are 6.02×10^23 atoms. So in two moles, there will be twice that: 1.204×10^24

6 0
3 years ago
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B. molecular weight I believe
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