What is the correct formula for tetraphosphorous octaoxide P4O10 P4O8 Ph4O8 P5O8
2 answers:
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Answer:
Final temperature of calorimeter is 25.36^{0}\textrm{C}
Explanation:
Molar mass of anethole = 148.2 g/mol
So, 0.840 g of anethole = of anethole = 0.00567 moles of anethole
1 mol of anethole releases 5539 kJ of heat upon combustion
So, 0.00567 moles of anethole release of heat or 31.41 kJ of heat
6.60 kJ of heat increases temperature of calorimeter.
So, 31.41 kJ of heat increases or
temperature of calorimeter
So, the final temperature of calorimeter =
Explanation:
It is given that r = 0.283 nm. As 1 nm = .
Hence, 0.283 nm =
- Formula for coulombic energy is as follows.
where, e = C
=
=
- As 1 eV =
So, 1 J =
Hence, U =
= 8.9 eV
- Also, 1 J =
= kJ/mol
Therefore, U = kJ/mol
=