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maksim [4K]
3 years ago
14

When 5.175 g of lead are heated at 300 C the lead reacts with the oxygen in the air to

Chemistry
2 answers:
TEA [102]3 years ago
4 0
2Pb+O_2=2PbO if the lead has valence 2 (I'm not totally certain of that, lol)
Scorpion4ik [409]3 years ago
4 0

Answer:

Mass of oxygen used is 5.708 – 5.175 g = 0.533 g Moles of lead reacting = (5.175/207) mol = 0.025 mol Moles of oxygen reacting = (0.533/32) mol = 0.0167 mol ∴0.025 mol of Pb react with 0.0167 mol of O2to give product ∴1.5 mol of Pb react with 1 mol of O2to give product ∴3 mol of Pb react with 2 mol of O2to give product 3Pb+ 2O2→Pb3O4You do not have the information to write the full equation but as you know there is only one product and this has 3 lead atoms and 4 oxygen you can suggest a formula.

Explanation:

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Magnesium hydroxide is only very slightly soluble in water. The reaction by which it goes into solution is: Mg(OH) 2 (s) rightle
prohojiy [21]

Answer:

there will a definite decrease in solute solution

Explanation:

acid reaction acting upon negative charge.

3 0
3 years ago
14. An enzyme-catalyzed reaction was carried out with the substrate concentration initially a thousand times greater than the Km
emmainna [20.7K]

Answer:

27 min

Explanation:

The kinetics of an enzyme-catalyzed reaction can be determined by the equation of Michaelis-Menten:

v = \frac{vmax[S]}{Km + [S]}

Where v is the velocity in the equilibrium, vmax is the maximum velocity of the reaction (which is directed proportionally of the amount of the enzyme), Km is the equilibrium constant and [S] is the concentration of the substrate.

So, initially, the velocity of the formation of the substrate is 12μmol/9min = 1.33 μmol/min

If Km is a thousand times smaller then [S], then

v = vmax[S]/[S]

v = vmax

vmax = 1.33 μmol/min

For the new experiment, with one-third of the enzyme, the maximum velocity must be one third too, so:

vmax = 1.33/3 = 0.443 μmol/min

Km will still be much smaller then [S], so

v = vmax

v = 0.443 μmol/min

For 12 μmol formed:

0.443 = 12/t

t = 12/0.443

t = 27 min

7 0
3 years ago
I NEED HELP!!!!!
wlad13 [49]

Answer: See explanation

Explanation:

The negative effects of video games include:

1. Social disconnection- One negative effect of video games is that it brings about social disconnection. Video games are typically addictive and this leads to the individual playing the game gradually disconnecting from the social life. Such people tends to play games rather than having conversations with their friends or family members.

2. Addiction - Video games are addictive which can lead to depression or bring about mental health disorder.

3. Wrong values - Some video games instill wrong values in children. Such values include violence, aggression and vengeance.  

4. Negative academic achievement - Students who play video games a lot tend to have a negative academic achievement as the time they could have used in reading or studying is used for playing games and thus tends to have an effect on the performance in school.

5. Health hazards- Video games may lead to health hazards- such as nerve compression, obesity, and video-induced seizures.

The positive effect of video games are:

1. Problem solving - Video games train ones brain to be creative and also come up with solution to challenges.

2. Quick thinking - Video games help one to think quickly in order to solve challenges and overcome obstacles.

3. Create positive emotions - Easy games can bring about positive emotions and uplift ones mood, and help in promoting relaxation.

4. Stimulate learning - Playing video games can help an individual to learn new skills.

8 0
3 years ago
2. Use the Henderson-Hasselbalch equation to estimate the pH of a buffer solution that is composed of 20 mL of 10 M sodium forma
Mkey [24]

Answer:

pH of buffer =4.75

Explanation:

The pH of buffer solution is calculated using Henderson Hassalbalch's equation:

pH=pKa+log[\frac{[salt]}{[acid]}

Given:

pKa = 3.75

concentration of acid = concentration of formic acid = 1 M

concentration of salt =  concentration of sodium formate = 10 M

pH=3.75+log[\frac{10}{1}]=3.75+1=4.75

pH of buffer =4.75

7 0
3 years ago
Orygon
grigory [225]

if 105 grams burns completely

therefore

105 ×22.4/48=49

8 0
3 years ago
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