Question

When 5.175 g of lead are heated at 300 C the lead reacts with the oxygen in the air to

Answer 1

$2Pb+O_2=2PbO$ if the lead has valence 2 (I'm not totally certain of that, lol)

Answer 2

Answer:

Mass of oxygen used is 5.708 – 5.175 g = 0.533 g Moles of lead reacting = (5.175/207) mol = 0.025 mol Moles of oxygen reacting = (0.533/32) mol = 0.0167 mol ∴0.025 mol of Pb react with 0.0167 mol of O2to give product ∴1.5 mol of Pb react with 1 mol of O2to give product ∴3 mol of Pb react with 2 mol of O2to give product 3Pb+ 2O2→Pb3O4You do not have the information to write the full equation but as you know there is only one product and this has 3 lead atoms and 4 oxygen you can suggest a formula.

Explanation: