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maksim [4K]
3 years ago
14

When 5.175 g of lead are heated at 300 C the lead reacts with the oxygen in the air to

Chemistry
2 answers:
TEA [102]3 years ago
4 0
2Pb+O_2=2PbO if the lead has valence 2 (I'm not totally certain of that, lol)
Scorpion4ik [409]3 years ago
4 0

Answer:

Mass of oxygen used is 5.708 – 5.175 g = 0.533 g Moles of lead reacting = (5.175/207) mol = 0.025 mol Moles of oxygen reacting = (0.533/32) mol = 0.0167 mol ∴0.025 mol of Pb react with 0.0167 mol of O2to give product ∴1.5 mol of Pb react with 1 mol of O2to give product ∴3 mol of Pb react with 2 mol of O2to give product 3Pb+ 2O2→Pb3O4You do not have the information to write the full equation but as you know there is only one product and this has 3 lead atoms and 4 oxygen you can suggest a formula.

Explanation:

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N2(g) + 3H2(g) → 2NH3(g) How many grams of N2 are required to produce 240.0g NH3?
just olya [345]

Answer:

\large \boxed{\text{197.4 g}}

Explanation:

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:     28.01               17.03

            N₂ + 3H₂ ⟶ 2NH₃

m/g:                          240.0

(a) Moles of NH₃

\text{Moles of NH}_{3} = \text{240.0 g NH}_{3}\times \dfrac{\text{1 mol NH}_{3}}{\text{17.03 g NH}_{3}}= \text{14.09 mol NH}_{3}

(b) Moles of N₂

\text{Moles of N$_{2}$} = \text{14.09 mol NH}_{3} \times \dfrac{\text{1 mol N$_{2}$}}{\text{2 mol NH}_{3}} = \text{7.046 mol N$_{2}$}

(c) Mass of N₂

\text{Mass of N$_{2}$} =\text{7.046 mol N$_{2}$} \times \dfrac{\text{28.01 g N$_{2}$}}{\text{1 mol N$_{2}$}} = \textbf{197.4 g N$_{2}$}\\\\\text{The reaction requires $\large \boxed{\textbf{197.4 g}}$ of N$_{2}$}

7 0
2 years ago
Read 2 more answers
4. Which of the following NOT TRUE about real gas
Semenov [28]

Answer:

The answer is D.

Explanation:

Intermolecular force are negligible

When the distance between molecules decrease,

the attraction or repulsion become greater

7 0
2 years ago
E)¿Cuántos átomos de oxigeno hay en la molécula de glucosa, al reaccionar 12moleculas de agua?
elena55 [62]

Answer:

12 átomos de oxígeno hay presentes

Explanation:

Basados en la reacción:

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂

<em>6 moles de agua producen 1 mol de glucosa</em>

<em />

Si reaccionan 12 moleculas de agua, se producirán:

12 moleculas H₂O * (1 mol C₆H₁₂O₆ / 6 mol H₂O) =

2 moléculas de glucosa se producen.

Como cada molécula de glucosa tiene 6 átomos de oxígeno:

2 moléculas C₆H₁₂O₆ * (6 átomos Oxígeno / 1 molécula C₆H₁₂O₆) =

<h3>12 átomos de oxígeno hay presentes</h3>

6 0
3 years ago
If calcium has two valence electrons and sulfur has six, how many calcium atoms are needed to form an ionic bond with sulfur?
Kipish [7]
3 calcium atoms would be needed.
3 0
2 years ago
Read 2 more answers
What is the molar mass of a gas if 0.281 g of the gas occupies a volume of 125 ml at a temperature 126 °c and a pressure of 777
AleksAgata [21]
<em>Answer :</em> 72.05 g/mol
<span>
<em>Explanation : </em>

Let's </span>assume that the given gas is an ideal gas. Then we can use ideal gas equation,<span>
PV = nRT<span>
</span>
Where, 
P = Pressure of the gas (Pa)
V = volume of the gas (m³)
n = number of moles (mol)
R = Universal gas constant (8.314 J mol</span>⁻¹ K⁻¹)<span>
T = temperature in Kelvin (K)
<span>
The given data for the gas </span></span>is,<span>
P = 777 torr = 103591 Pa
V = </span>125 mL = 125 x 10⁻⁶ m³<span>
T = (</span>126 + 273<span>) = 399 K
R = 8.314 J mol</span>⁻¹ K⁻¹<span>
n = ?

By applying the formula,
103591 Pa x  </span>125 x 10⁻⁶ m³ = n x 8.314 J mol⁻¹ K⁻¹ x 399 K<span>
                                          n = 3.90 x 10</span>⁻³<span> mol

</span>Moles (mol) = mass (g) / molar mass (g/mol)<span>

Mass of the gas = </span><span>0.281 g
</span>Moles of the gas = 3.90 x 10⁻³ mol
<span>Hence,
   molar mass of the gas = mass / moles
                                          = 0.281 g / </span>3.90 x 10⁻³ mol
<span>                                          = 72.05 g/mol

</span>
7 0
3 years ago
Read 2 more answers
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