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Leya [2.2K]
3 years ago
13

How many protons z and how many neutrons n are there in a nucleus of the most common isotope of silicon, 2814si? separate your a

nsw?
Chemistry
1 answer:
Maksim231197 [3]3 years ago
3 0
The Atomic Number and Atomic Mass of ²⁸Si₁₄ are 14 and 28 respectively.

Atomic Number:
                         Atomic Number of Element is the Number of Protons contained by the Element. So, there are 14 Protons in ²⁸Si₁₄.

Atomic Mass:
                     Atomic Mass of Element is the total number of Protons and Neutrons present in the Nucleus of that element.
So,
                    Atomic Mass  =  # of Protons + # of Neutrons

As the Atomic mass of ²⁸Si₁₄ is 28 and it has 14 protons, So # of Neutrons are calculated as,

                     # of Neutrons  =  Atomic Mass - # of Protons

                     # of Neutrons  =  28 - 14

                     # of Neutrons  =  14

Result:
             In ²⁸Si₁₄ Number of Neutrons are 14, Number of Protons are 14.

                                             Z  =  14 , n  =  14
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Answer:

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Explanation:

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\displaystyle n = \frac{m}{M} = \frac{16.3}{24.301} = 0.670644\;\text{mol}.

The ratio between the coefficient of Mg and that of MgO is 2:2. Two moles of Mg will make two moles of MgO. 0.670644 moles of MgO will be produced if Mg is the limiting reactant.

How many moles of MgO will be produced if O₂ is the limiting reactant?

Number of moles of O₂:

\displaystyle n = \frac{m}{M} = \frac{4.33}{15.999} = 0.270642\;\text{mol}.

The ratio between the coefficient of O₂ and that of MgO is 1:2. One mole of O₂ will make two moles of MgO. 2\times 0.270642 = 0.541284\;\text{mol} of MgO will be produced if O₂ is in excess.

How many moles of MgO will be produced?

0.541284 is smaller than 0.670644. Only 0.541284 moles of MgO will be produced since O₂ will run out before all 16.3 grams of Mg is consumed.

What's the mass of 0.541284 moles of MgO?

Formula mass of MgO:

24.301 + 15.999 = 40.300\;\text{g}\cdot\text{mol}^{-1}.

Mass of 0.541284 moles of MgO:

m = n \cdot M = 0.541284\times 40.300 = 21.8\;\text{g}.

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