Question

How many protons z and how many neutrons n are there in a nucleus of the most common isotope of silicon, 2814si? separate your answ?

Answer 1

The Atomic Number and Atomic Mass of ²⁸Si₁₄ are 14 and 28 respectively.

Atomic Number:
                         Atomic Number of Element is the Number of Protons contained by the Element. So, there are 14 Protons in ²⁸Si₁₄.

Atomic Mass:
                     Atomic Mass of Element is the total number of Protons and Neutrons present in the Nucleus of that element.
So,
                    Atomic Mass  =  # of Protons + # of Neutrons

As the Atomic mass of ²⁸Si₁₄ is 28 and it has 14 protons, So # of Neutrons are calculated as,

                     # of Neutrons  =  Atomic Mass - # of Protons

                     # of Neutrons  =  28 - 14

                     # of Neutrons  =  14

Result:
             In ²⁸Si₁₄ Number of Neutrons are 14, Number of Protons are 14.

                                             Z  =  14 , n  =  14