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Archy [21]
3 years ago
13

Rewrite f(x) = 3(x − 2)2 + 1 from vertex form to standard form.

Mathematics
1 answer:
Tom [10]3 years ago
6 0

Answer:

f(x) = 9x^2-36x+37

Step-by-step explanation:

3(x-2)^2+1

(3x-6)^2+1

9x^2-36x+36+1

9x^2-36x+37

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What is the quotient ? a-3/7 divided by 3-a/21
LUCKY_DIMON [66]
Final result :  -3



Step by step solution :Step  1  :            3 - a Simplify   —————             21  Equation at the end of step  1  :  (a - 3)   (3 - a)  ——————— ÷ ———————     7        21   Step  2  :            a - 3 Simplify   —————              7  Equation at the end of step  2  :  (a - 3)   (3 - a)  ——————— ÷ ———————     7        21   Step  3  :         a-3      3-a Divide  ———  by  ———          7       21 
 3.1    Dividing fractions 
To divide fractions, write the divison as multiplication by the reciprocal of the divisor :
a - 3     3 - a       a - 3        21  —————  ÷  —————   =   —————  •  ———————  7        21           7       (3 - a)
 3.2    Rewrite   (3-a)    as  (-1) •  (a-3) Canceling Out : 3.3    Cancel out  (a-3)  which now appears on both sides of the fraction line.
Final result :  -3
4 0
3 years ago
Read 2 more answers
PLS HELP
Fiesta28 [93]

Answer:

1. 1/3 x 2/2 = 1/3

2. 1/4 x 5/5 = 1/4

3. 1/6 x 4/4 = 1/6

4. 9/8 x 3/4 = (9x3)/(8x4) = 27/32

4. 4/5 x 2/2 = 4/5

Step-by-step explanation:

n/n = 1

7 0
3 years ago
Can anyone explain step by step how to get this answer?<br><br><br> Will mark branliest!!
Y_Kistochka [10]

Answer:

Step-by-step explanation:

28°

4 0
3 years ago
Read 2 more answers
I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

7 0
4 years ago
URGENT PLEASE HELP
Inga [223]

Answer:

y = - \frac{1}{3} x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x - 3 ← is in slope- intercept form

with slope m = 3

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{3}, hence

y = - \frac{1}{3} x + c ← is the partial equation of the perpendicular line

To find c substitute (3, 1) into the partial equation

1 = - 1 + c ⇒ c = 1 + 1 = 2

y = - \frac{1}{3} x + 2 ← equation of perpendicular line

4 0
3 years ago
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