Answer:
ANS : .Energy spent on spraying =
Explanation:
<em>Given:</em>
- <em>Radius of mercury = 1cm initially ;</em>
- <em>split into
drops ;</em>
Thus, volume is conserved.
i.e ,
- Energy of a droplet =
Δ
Where ,
- <em>T is the surface tension </em>
- <em>ΔA is the change in area</em>
Initial energy 
Final energy 
∴ .Energy spent on spraying = 
ANS : .Energy spent on spraying =
A wave with a period of 1⁄3 second has a frequency of D. 3 Hz. To
calculate this we will use the formula that represents the correlation
between a frequency (f) and a time period (T): T = 1/f. Or: f = 1/T. The
unit for the time period is second "s" while the unit for frequency is
Hertz "Hz" (=1/s). We know that T = 1/3 s. That means that f = 1/(1/3s) =
3 1/s = 3 Hz.
Distance = speed x time
= 1.5 x 6
= 9m
I think the correct answer would be old and metal poor stars are found in the galactic nucleus. This nucleus us a region in the center of a galaxy which contains a higher luminosity than other parts. It produces very high amounts of energy. Hope this helps.
