Using the formula for permutation, there are 5040 ways that 7 objects are taken 1 at a time.
<h3>What is permutation?</h3>
The permutation of objects refers to the number of ways that an object can be selected from a number of objects.
Given that;
nPr = n!/(n - r)!
Hence;
7P1 = 7!/(7 - 1)!
7P1 = 7 * 6 !/6!
7P1 = 7 * 6 * 5 * 4 * 3 * 2 *1
7P1 = 5040
Learn more about permutation: brainly.com/question/1216161
The rocket would have gone 125 m away in deep space.The speed when it has gone 300 m is 76.7 m/s.
Answer:
The distance the rocket traveled is 125 m. The speed when it has gone 300 m is 76.7 m/s.
Explanation:
According to the equations of motion, if an object is moving with constant acceleration, then the distance travelled by the object with that acceleration and within a specific time can be obtained as
![s=ut+\frac{1}{2}at^{2}](https://tex.z-dn.net/?f=s%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E%7B2%7D)
Since the initial velocity is given as u = 0 at t = 0. Then at t = 10 s, the acceleration is given by 2.5 m/
.
Thus,
s= 0 + (
×2.5×
)=125 m.
Thus, the rocket would have gone 125 m away in deep space.
Similarly, if it had gone 300 m then its speed can be determined using the third equation of motion.
![2as = v^{2} -u^{2}](https://tex.z-dn.net/?f=2as%20%3D%20v%5E%7B2%7D%20-u%5E%7B2%7D)
Since, here v is unknown and u is known as 0 with a = 2.5 m/
.
2× 9.8×300=v²
5880=v²
Thus, the speed v = ![\sqrt{5880}=76.7 m/s](https://tex.z-dn.net/?f=%5Csqrt%7B5880%7D%3D76.7%20m%2Fs)
So, the speed when it has gone 300 m is 76.7 m/s.
Explanation:
To find the answer use the equation speed of light=wavelength multiplied by frequency (c=lambda*f) by substituting the value for the frequency the the speed of light
Air pressure decreases with altitude
hope that helps you!
The resistance that one surface or object encounters when moving over another.
"a lubrication system that reduces friction”