Answer:
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https://www.flinnsci.com/api/library/Download/18ce587821c24fb3b0ad7d878bd6a3d9Explanation:
Answer:
b) The molecule has a molecular weight under 200 g/mole
Explanation:
The molecule has a molecular weight under 200 g/mole is the primary requirement for a molecule to be analyzed by Gas Chromatography.
Answer:
I)Acetylene
II)2-Methyl-1-butanol
Explanation:
I)appears as a colorless gas with a faint garlic-like odor. Easily ignited and burns with a sooty flame. Gas is lighter than air.
The composition, in atom percent, of an alloy that consists of 30 wt% Zn and 70 wt% Cu is 29.4 at % and 70.6 at % for Zn and Cu respectively.
<h3>How to convert weight % to atom %?</h3>
The weight percentage of an element can be converted to atom percentage as follows:
- C(Zn) = C1A2 / (C2A1) + (C1A2) × 100
- C(Cu) = C2A1 / (C1A2) + (C2A1) × 100
Where;
- C1 = 30
- C2 = 70
- A1 = 65.4g/mol
- A2 = 63.55g/mol
- C(Zn) = {30*63.55} / (70*65.4) + (30*63.55) × 100
- C(Cu) = {70*65.4} / (30*63.55) + (70*65.4) × 100
- C(Zn) = 29.4 at %
- C(Cu) = 70.6 at %
Therefore, the composition, in atom percent, of an alloy that consists of 30 wt% Zn and 70 wt% Cu is 29.4 at % and 70.6 at % for Zn and Cu respectively.
Learn more about atomic percent at: brainly.com/question/10018123
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