Which is always true of a salt?

Be sure to answer all parts. identify and label the species in each reaction. (a) nh4+(aq) + h2o(l) ⇌ nh3(aq) + h3o+(aq) acid ba

quester [9]

A)

NH⁴⁺(aq) + H₂O(l) ⇌ NH₃(aq) + H₃0⁺(aq)

- acid a species that able to donate (H+): NH⁴⁺
- base a species that is able to accept a proton (H+): H₂O
- conjugate base a species formed when acid donates a proton (H+): NH₃
- conjugate acid a species formed by a base accepts a proton (H+): H₃0⁺

b)

CN⁻(aq) + H₂O(l) ⇌ HCN(aq) + OH⁻(aq)

- base a species that is able to accept a proton (H+): CN⁻
- acid a species that able to donate (H+): H₂O
- conjugate acid a species formed by a base accepts a proton (H+): HCN
- conjugate base a species formed when acid donates a proton (H+): OH⁻

5 0

4 years ago

Which one of these is NOT a sign of chemical change? *

Gekata [30.6K]

I think it’s light
Have fun :)

3 0

3 years ago

Consider these elements: p, ca, si, s, ga. a. write the electron configuration for each element

dimulka [17.4K]

Method:

1) Find the atomic number in a periodic table: the number of electrons equal the atomic number

2) Use Aufbau rule

Element atomic number electron configuration

P 15 1s2 2s2 2p6 3s2 3p3

Ca 20 1s2 2s2 2p6 3s2 3p6 4s2

Si 14 1s2 2s2 2p6 3s2 3p2

S 16 1s2 2s2 2p6 3s2 3p4

Ga 31. 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p

7 0

4 years ago

Please help it’s due today I will give brainliest

Thepotemich [5.8K]

1st and 4th options are suitable answers, as these 2 changes are not exactly physical changes as it cant return back to original form and as well as its not cooling, so I feel its 1st and 4th options

7 0

3 years ago

A 215-g sample of copper metal at some temperature is added to 26.6 g of water. The initial water temperature is 22.22 oC, and t

andrezito [222]

The initial temperature of the copper metal was 27.38 degrees.

Explanation:

Data given:

mass of the copper metal sample = 215 gram

mass of water = 26.6 grams

Initial temperature of water = 22.22 Degrees

Final temperature of water = 24.44 degrees

Specific heat capacity of water = 0.385 J/g°C

initial temperature of copper material , Ti=?

specific heat capacity of water = 4.186 joule/gram °C

from the principle of:

heat lost = heat gained

heat gained by water is given by:

q water = mcΔT

Putting the values in the equation:

qwater = 26.6 x 4.186 x (2.22)

qwater = 247.19 J

qcopper = 215 x 0.385 x (Ti-24.4)

= 82.77Ti - 2019.71

Now heat lost by metal = heat gained by water

82.77Ti - 2019.71 = 247.19

Ti = 27.38 degrees

8 0

3 years ago