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shepuryov [24]
3 years ago
12

Which is always true of a salt?

Chemistry
1 answer:
igomit [66]3 years ago
3 0
Third one is correct .
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Select the property that is not a characteristic of an ideal recrystallization solvent.
dybincka [34]

Answer:

(C) The recrystallization solvent should be nonvolatile.

Explanation:

Recrystallization is the separation technique which is used to purify the solid compounds in their crystal or amorphous form.

Some properties follow the recrystallization process as:

The solids are more soluble in hot solvent as compared to the solubility in the cold solvent.

The solvent must have lower boiling point and can be volatile easily.

The solvent should not react with the compound.

The impurities must be soluble in the cool solvent, so that only the pure product crystallizes.

Hence, Answer - C which is not an ideal characteristic.

8 0
3 years ago
Bakit mahalaga ang paghahanda ng pambansang badyet sa isang taon?​
Andreas93 [3]

Answer:

no lo sé chico ve a morir en un agujero

Explanation:

8 0
3 years ago
A radioactive sample has a half-life of 5 hours. What fraction of the sample will be left after 15 hours?​
DedPeter [7]

Explanation:

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6 0
3 years ago
If you know the poh of a solution how can you determine its ph
Sati [7]
POH+pH=14,
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pH=14-pOH
7 0
3 years ago
The standard reduction potentials of lithium metal and chlorine gas are as follows:Reaction Reduction potential(V)Li+(aq)+e−→Li(
meriva

Answer:

A) E° = 4.40 V

B) ΔG° = -8.49 × 10⁵ J

Explanation:

Let's consider the following redox reaction.

2 Li(s) +Cl₂(g) → 2 Li⁺(aq) + 2 Cl⁻(aq)

We can write the corresponding half-reactions.

Cathode (reduction): Cl₂(g) + 2 e⁻ → 2 Cl⁻(aq)      E°red = 1.36 V

Anode (oxidation):  2 Li(s) → 2 Li⁺(aq) + 2 e⁻         E°red = -3.04

<em>A) Calculate the cell potential of this reaction under standard reaction conditions.</em>

The standard cell potential (E°) is the difference between the reduction potential of the cathode and the reduction potential of the anode.

E° = E°red, cat - E°red, an = 1.36 V - (-3.04 V) 4.40 V

<em>B) Calculate the free energy ΔG° of the reaction.</em>

We can calculate Gibbs free energy (ΔG°) using the following expression.

ΔG° = -n.F.E°

where,

n are the moles of electrons transferred

F is Faraday's constant

ΔG° = - 2 mol × (96468 J/V.mol) × 4.40 V = -8.49 × 10⁵ J

8 0
3 years ago
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