Answer:
1Ag+2S⇔1Ag2S
Explanation:
The first step is to see how many of each element are on each side of the equation. There is one silver on the left and one silver on the right, so you can leave those alone. However, there is one sulfur on the left and two on the right. You cannot multiply the right by 2 because then that would upset the balance of the silver, but you can multiply the sulfur by 2. Therefore, the equation should be 1Ag+2S⇔1Ag2S. Hope this helps!
The subscriot 2 means that in the formula there are two parts of K, and the subscript 1 (implicit) for S, indicates that there is one part of S.
This is, the formula gives the ratio of the elements K and S in the compound, which is:
2 atoms of K : 1 atom of S.
Answer: there are 2 atoms of K and 1 atom of S in a molecule of K2S.
Luster is your answer. Hope this helps.
-Belle
The general formula of an acid is HX where H+ acts as the cation while X can be a halogen (Cl-, Fl-, Br-, etc) and acts as the anion. There are also cases where X is an ion like SO42-, which brings two atoms of H in the formula. Strong acids dissociate completely while weak acids do not.
Answer:
Explanation:
The objective of this question is all about identifying the phenomena that holds true for the statement being said in each instance. Let; walk through them.
a) Whenever you see 9 or a multiple of 9 in the integration ratio, which group should you first consider for being responsible for that signal.
( C₄H₉ )Tert. Butyl group
b) Whenever you see a quartet and triplet on a spectrum, which group should you first consider for being responsible for those signals?
(CH₃CH₂) ethyl group
c) Whenever you see septet and a doublet on a spectrum, which group should you first consider for being responsible for those signals?
(CH(CH₃)₂) isoproply group
d) Whenever you see 6 or a multiple of 6 in the integration ratio, which group should you first consider for being responsible for that signal
(CH(CH₃)₂) isoproply group
e) Whenever you see 3 as the actual number of protons for a given signal, which group should you first consider for being responsible for that signal.
CH₃- methyl group
A perfect description showing the explanation of each answers chosen is explained with an aid of diagram below.