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zepelin [54]
3 years ago
15

Write the general chemical formula for an acid, and discuss what each component of the formula represents.

Chemistry
2 answers:
saul85 [17]3 years ago
4 0
The general formula of an acid is HX where H+ acts as the cation while X can be a halogen (Cl-, Fl-, Br-, etc) and acts as the anion. There are also cases where X is an ion like SO42-, which brings two atoms of H in the formula. Strong acids dissociate completely while weak acids do not.
Amiraneli [1.4K]3 years ago
4 0

<u>Answer:</u> The general chemical formula for an acid is given below.

<u>Explanation:</u>

Acids are defined as the chemical species which donate hydrogen ions when dissolved in water.

The general chemical formula for an acid follows:

HA(aq.)\rightarrow H^+(aq.)+A^-(aq.)

where,

H^+ is the cationic part and is named as hydrogen ions

A^- is the anionic part.

The nomenclature of the acids that are derived from the anions attached to hydrogen ion:

  • If the name of the anion attached ends with -ate, then the prefix of the acid is -ic. <u>For Example:</u> H_3PO_4, the anion is phosphate and the name of the acid is phosphoric acid.
  • If the name of the anion attached ends with -ite, then the prefix of the acid is -ous. <u>For Example:</u> H_2SO_3, the anion is sulfite and the name of the acid is sulfurous acid.
  • If the name of the anion attached ends with -ide, then the prefix of the acid is -ic. <u>For Example:</u> HCl, the anion is chloride and the name of the acid is hydrochloric acid.

Hence, the general chemical formula for an acid is given above.

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3 years ago
Part A
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Answer:

The answer to your question is below

Explanation:

A.

[H₃O⁺] = 2 x 10⁻¹⁴ M

pH = ?

Formula

                                    pH = - log [H₃O⁺]

Substitution

                                    pH = - log [2 x 10⁻¹⁴]

Result

                                    pH = 13.7          

B.

[H₃O⁺] = ?

pH = 3.12

Formula

                                   pH = - log [H₃O⁺]

Substitution

                                   3.12 = - log [H₃O⁺]

                                   10^{-3.12} = [H_{3} O^{+}]

Result

                                  [H₃O⁺] = 7.59 M

   

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