Explanation:
The two isotopes of lithium given are similar in the sense that they have the same atomic number which is 3.
Every kind of an atom of an element have the same atomic number. Atomic number is the number of protons in an atom.
The atoms are different in that they have different mass number because the number of protons they contain are different.
So for isotopes;
- They have the same electronic configuration
- They have similar chemical properties
- But their masses differs
- Their abundance in nature also differs.
Answer:
212.996 or 213 approx.
hope it helps.
Molar mass of Al - 27
Molar mass of N - 14
Molar mass of O - 16
so, the molar mass of (No3)3 will be (14+16×3)3 which is equals to 186.
so, Molar mass of Al(No3)3 will be 186+27 = 213.
<span>The density of the solution =1.05 g/ml.
</span><span>The total mass of the resulting solution is = 398.7 g (CaCl2 + water)
</span>
Find moles of CaCl2 and water.
Molar mass of CaCl2 = 110 (approx.)
Moles of CaCl2 = 23.7 / 110 = 0.22
so, moles of Cl- ion = 2 x 0.22 = 0.44 (because each molecule of CaCl2 will give two Cl- ions)
Moles of water = 375 / 18 = 20.83
Now, Mole fraction of CaCl2 = (moles of CaCl2) / (total moles)
total moles = moles of Cl- ions + moles of Ca2+ ions + moles of water
= 0.44 + 0.22 + 20.83
=21.49
So, mole fraction = 0.44 / (21.49) = 0.02
Guess what !!! density is not used. No need
Acetylsalicylic acid (ASA) or commonly known as aspirin is used as pain reliever, treatment for fever and inflammation. The type of bond that aspirin have is covalent bond. Covalent bond is when atoms share their electrons. Aspirin is made up of carbon, hydrogen and oxygen with a formula of C9H8O4.
Answer:
The mass percentage is 3.26 %.
Explanation:
The reaction between acetic acid and NaOH will be:
Thus one mole of acetic acid will react with one mole of NaOH.
The moles of NaOH used = molarity X volume = 0.1 X 30.10 mL = 3.010 mmol
The moles of acetic acid reacted = 3.010 mmol
The moles of acetic acid will be used to calculate the mass of acetic acid used
Mass of acetic acid used = moles X molar mass = 3.010mmol X 60
mass of acetic acid used = 180.6 mg = 0.1806 g
The mass of vinegar used = 5.54 g
The percentage of acetic acid in vinegar will be =%