Question

An 18 liter container holds 16.00 grams of oxygen gas (o2 at 45 °c. what is the pressure in the container?

Answer 1

Hello!

The pressure of an 18 L container which holds 16,00 grams of oxygen gas (O₂) at 45 °C is 0,725 atm

To solve this problem we first need to set up the data in the appropriate units to input it in the Ideal Gas Law.

a) 16 g of Oxygen gas to moles of oxygen gas:

$16gO_2* \frac{1 mol O_2}{32gO_2}=0,5 mol O_2$

b) 45 °C to K

$K= ^{\circ} C + 273,15 = 45 ^{\circ} C + 273.15=318,15 K$

Now, we clear the Ideal Gas Equation for P, and solve it:

$P*V=n*R*T \\ \\ P= \frac{n*R*T}{V}= \frac{(0,5mol)*(0,082 \frac{L*atm}{mol*K})* (318,15 K)}{18 L}= 0,725 atm$

Have a nice day!