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icang [17]
3 years ago
11

A 1.25 g sample of aluminum is reacted with 3.28 g of copper (II) sulfate. What is the limiting reactant? 2Al(s) + 3CuSO4(aq) →

Al2(SO4)3(aq) + 3Cu(s)
Aluminum
Copper
Copper (II) sulfate
Aluminum sulfate
Chemistry
1 answer:
vova2212 [387]3 years ago
7 0

Answer:

Copper (II) sulfate

Explanation:

Given reaction is

2Al(s) + 3CuSO4(aq) → Al2(SO4)3(aq) + 3Cu(s)

Amount of aluminum = 1·25 g

Amount of copper (II) sulfate = 3·28 g

Atomic weight of Al = 26 g

Molecular weight of CuSO4 ≈ 159·5

Number of moles of Al = 1·25 ÷ 26 = 0·048

Number of moles of CuSO4 = 3·28 ÷ 159·5 = 0·021

From the above balanced chemical equation for every 2 moles of aluminum, 3 moles of copper (ll) sulfate will be required

So for 1 mole of Al, 1·5 moles of copper (ll) sulfate will be required

For 0·048 moles of Al, 1.5 × 0·048 moles of copper (ll) sulfate will be required

∴ Number of moles of copper (ll) sulfate required = 0·072

But we have only 0·021 moles of copper (ll) sulfate

As copper (ll) sulfate is not there in required amount, the limiting reactant will be copper (ll) sulfate

∴ The limiting reactant is copper (ll) sulfate

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spin [16.1K]
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How many neutrons are there in 8 molecules of <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B19%7D%7B9%7D%20f2" id="TexFormu
slega [8]

Answer:

128 neutrons

Explanation:

<em>How many neutrons are there in 8 molecules of </em>^{19} _9 F_2<em>?</em>

Step 1: Calculate the number of neutrons in 1 atom of F.

The atomic number (z) of F is 9 and its mass number (A) is 19. We can calculate the number of neutrons using the following expression.

n⁰ = A - Z = 19 - 9 = 10

Step 2: Calculate the number of neutrons in 1 molecule of F₂.

1 molecule of F₂ contains 2 atoms of F. The number of neutrons in  1 molecule of F₂ is:

(8 n⁰/1 atom F) × (2 atom F/1 molecule F₂) = 16 n⁰/1 molecule F₂

Step 3: Calculate the number of neutrons in 8 molecules of F₂

8 molecule F₂ × 16 n⁰/1 molecule F₂ = 128 n⁰

4 0
3 years ago
Which is the safest method for diluting concentrated sulfuric acid with water?
Anton [14]

The safest method for diluting concentrated sulfuric acid with water is to add acid to water. This way, when spill occurs, the acid is already diluted and less harmful than adding water to acid.

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Use the "x is small" approximation to find the concentration of the products in the following reaction which initially contains
Mrrafil [7]

Answer:

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[CN^-]=0.0000229 M

Explanation:

HCN(aq)\rightleftharpoons H^+(aq) + CN^-(aq)

initially

0.85 M        0    0

(0.85-x)M    x      x

The equilibrium constant of reaction = K_c= 6.17\times 10^{-10}

The expression of an equilibrium cannot can be written as:

K_c=\frac{[H^+][CN^-]}{[HCN]}

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Solving for x:

x = 0.0000229

Concentration of product at equilibrium ;

[H^+]=0.0000229 M

[CN^-]=0.0000229 M

4 0
3 years ago
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