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Neko [114]
2 years ago
9

In the reaction A + B + C + D, what are the products?

Chemistry
1 answer:
gayaneshka [121]2 years ago
6 0

Answer:

Sorry; this looks like some specific point from class or your book. I can think of each one and create a synthesis, but that isn’t what this is.

Explanation:

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What is the most likely reason that nonmetals are electrical insulators?
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Since valence shells are mostly empty in nonmetal atoms, the atoms attract and hold any electrons they can in order to fill their valence shells.

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How does an atom change if all of its electrons are removed?<br> .
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If an atom looses all of its electrons then it will become positively charged. It will also turn into an Ion.

Explanation:

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Is it possible to transfer heat from a cold reservoir to a hot reservoir?
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Answer is: B.) Yes, if work is done, this transfer process can take place.

For example,  air conditioner involves a cyclic process that transfers heat from a cold reservoir to a hot reservoir, but with use of electricity.

Thermal conductuction is the transfer of heat through physical contact. Thermal conduction is the transfer of heat by microscopic collisions of particles. Heat spontaneously flows from a hotter to a colder body.

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What are some examples of minerals that occur as elements instead of<br>compounds​
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3 0
3 years ago
calculate the wavelength of light associated with the transition from n=1 to n=3 in the hydrogen atom?
inessss [21]

<u>Answer:</u>

\Delta E=E_{final}-E_{initial}

\Delta E=-1312[\frac{1}{(n_f^2)}-\frac {1}{(n_i^2 )}]KJ mol^{-1}

\Delta E=-1312[\frac{1}{3^2)}-\frac {1}{(1^2 )}]KJ mol^{-1}

\Delta E=-1312[\frac{1}{(9)}-\frac {1}{(1 )}]KJ mol^{-1}

\Delta E=-1312[0.111-1]KJ mol^{-1}

\Delta E=1166 KJ mol^{-1}

\frac{=1166,000 \mathrm{J}}{6.022 \times 10^{23} \text { photons }}

=193623 \times 10^{-23}  \frac {J}{photon}

\Delta E=1.93623 \times 10^{-18}  \frac {J}{photon}

\Delta E=\frac {h\times c}{\lambda} \\\\=\frac {(6.626\times 10^{-34} J s \times 3 \times 10^8 ms^{-1})}{\lambda}

h is planck's constant  

c is the speed of light

λ is the wavelength of light  

\lambda =\frac {h\times c}{\Delta E}\\\\=\frac {(6.626\times10^{-34} J s\times3 \times 10^8 ms^{-1})}{(1.93623\times10^{-18}  J/photon)}

Wavelength

\lambda =10.3 \times 10^{-8} m \times \frac {(10^9 nm)}{1m}  =103 nm (Answer)

<em>Thus, the wavelength of light associated with the transition from n=1 to n=3 in the hydrogen atom is </em><u><em>103 nm.</em></u>

7 0
2 years ago
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