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Neko [114]
3 years ago
9

In the reaction A + B + C + D, what are the products?

Chemistry
1 answer:
gayaneshka [121]3 years ago
6 0

Answer:

Sorry; this looks like some specific point from class or your book. I can think of each one and create a synthesis, but that isn’t what this is.

Explanation:

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Hydrobromic acid, HBr, is a strong acid. Hydrofluoric acid, HF, is a weak acid. If you prepared equal
snow_tiger [21]
HBr and HF are both monoprotic Arrhenius acids—that is, in aqueous solution, they dissociate and ionize to give hydrogen ions. A strong acid ionizes completely; a weak acid ionizes partially.

In this case, HBr, being a strong acid, would ionize completely in water to yield H+ and Br- ions. However, HF, being a weak acid, would ionize only to a limited extent: some of the HF molecules will ionize into H+ and F- ions, but most of the HF will remain undissociated.

pH is, by definition, a measurement of the concentration of hydrogen ions in solution (pH = -log[H+]). A higher concentration of hydrogen ions gives a lower pH, while a lower concentration of hydrogen ions gives a higher pH. At 25 °C, a pH of 7 indicates a neutral solution; a pH less than 7 indicates an acidic solution; and a pH greater than 7 indicates a basic solution.

If we have equal concentrations of HBr and HF, then the HBr solution will have a greater concentration of hydrogen ions in solution than the HF solution. Consequently, the pH of the HBr solution will be less than the pH of the HF solution.

Choice A is incorrect: Strong acids like HBr dissociate completely, not partially.

Choice B is incorrect: While the initial concentration of HBr and HF are the same, the H+ concentration in the HBr solution is greater. Since pH is a function of H+ concentration, the pH of the two solutions cannot be the same.

Choice C is correct: A greater H+ concentration gives a lower pH value. The HBr solution has the greater H+ concentration. Thus, the pH of the HBr solution would be less than that of the HF solution.

Choice D is incorrect for the reason why choice C is correct.

4 0
2 years ago
Give the correct balanced equation for the single replacement reaction of magnesium with aluminum oxide. A) Mg + AlO → MgO + Al
solniwko [45]
Answer is "C".

<em><u>Explanation
</u></em>

Single replacement reaction is a type of reaction which one reactant reacts with another and makes a product by replacing one element by another. 

Mg (Magnesium) reacts with Al₂O₃ (Aluminium oxide) and produces MgO (Magnesium oxide) and Al (Aluminium) as products. Here Al is replaced by Mg. Reaction is 
             Mg + Al₂O₃ → MgO + Al

To balance the reaction equation, both left and right hand sides should have same number of atoms in each element.
Here, 
 <em>Left Hand Side has </em>                                            <em>Right Hand Side has</em>
   Mg = 1 atom                                                         Mg = 1 atom
   Al = 2 atom                                                           Al = 1 atom
   O = 3 atom                                                           O = 1 atom

First step : balance the O atoms in both sides. To do that "3" should be added before MgO. 

Second step : After balancing O atoms, there will be 3 Mg atoms in right hand side. Hence to balance Mg atoms again "3" should be added before Mg in left hand side

Third step : as the final step balance the Al atoms by adding "2" before Al in the right hand side.

Then final balanced equation should be 
              3Mg + Al₂O₃ → 3MgO + 2Al



 
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Compounds are made of two or more atoms of different elements, such as water (H2O) and methane (CH4). Atoms are not drawn to scale. Molecules of compounds have atoms of two or more different elements.
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The correct answer to this question is that the length of 14 is it’s half Which would be 7
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